⚠️I MARK BRAINLIST I AM BRING TIMED PIC INCLUDED⚠️Match the stage of the product development life cycle to the product that best
represents it.
building complex systems
car engines employed for more than one model
reusing technology
sophisticated jet airliners
pushing a technology to market
the latest iPhone version
building complex systems
car engines employed for more than one model
reusing technology
sophisticated jet airliners
pushing a technology to market
the latest iPhone version
1 answer:
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Answer:
The strength coefficient is and the strain-hardening exponent is
Explanation:
Given the true strain is 0.12 at 250 MPa stress.
Also, at 350 MPa the strain is 0.26.
We need to find and the
.
We will plug the values in the formula.
We will solve these equation.
plug this value in
Taking a natural log both sides we get.
Now, we will find value of
So, the strength coefficient is and the strain-hardening exponent is
.
Answer:
the answer is below
Explanation:
a) The conductivity of graphite (σ) is calculated using the formula:
where f = frequency = 100 MHz, δ = skin depth = 0.16 mm = 0.00016 m, μ = 0.0000012
Substituting:
b) f = 1 GHz = 10⁹ Hz.
This question is incomplete, the complete question is;
(Laminar flow) A fluid flows through two horizontal pipes of equal length which are connected together to form a pipe of length 2. The flow is laminar and fully developed. The pressure drop for the first pipe is 1.657 times greater than it is for the second pipe. If the diameter of the first pipe is D, determine the diameter of the second pipe.
D₃ = _____D.
{ the tolerance is +/-3% }
Answer:
the diameter of the second pipe D₃ is 1.13D
Explanation:
Given the data in the question;
Length = 2
pressure drop in the first pipe is 1.657 times greater than it is for the second pipe.
Now, we know that for Laminar Flow;
V' = πD⁴ΔP / 128μL
where V'₁ = V'₂ and ΔP₁₋₂ = 1.657 ΔP₂₋₃
Hence,
V'₁ = πD⁴ΔP₁₋₂ / 128μL = V'₃ = πD₃⁴ΔP₂₋₃ / 128μL
so
D₃ = D ΔP₁₋₂ / ΔP₂₋₃
we substitute
D₃ = D 1.657
D₃ = D( 1.134568 )
D₃ = 1.13D
Therefore, the diameter of the second pipe D₃ is 1.13D