Answer:
15.3 %
Explanation:
Step 1: Given data
- Mass of the sample (ms): 230 g
- Mass of carbon (mC); 136.6 g
- Mass of hydrogen (mH): 26.4 g
- Mass of nitrogen (mN): 31.8 g
Step 2: Calculate the mass of oxygen (mO)
The mass of the sample is equal to the sum of the masses of all the elements.
ms = mC + mH + mN + mO
mO = ms - mC - mH - mN
mO = 230 g - 136.6 g - 26.4 g - 31.8 g
mO = 35.2 g
Step 3: Calculate the mass percent of oxygen
%O = (mO / ms) × 100% = (35.2 g / 230 g) × 100% = 15.3 %
Answer:

Explanation:
From the question we are told that:
Moles of sample n=3.20_mol
Volume V=350mL
Temperature T=300k
Generally the equation for ideal gas is mathematically given by





Answer:
[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter
Explanation:
The pH is calculated with the formula:
pH = -lg[H₃O⁺]
From here the concentration of hydronium ion (H₃O⁺) will be:
[H₃O⁺] = 
[H₃O⁺] = 
[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter
Answer:
80.0 g Na and 20.0 g N2.
Explanation:
This means the limiting reactant determines the maximum mass of the product formed.
Answer:
Hope this helps
Explanation:
https://seagrant.whoi.edu/wp-content/uploads/2018/05/ESTIMATING-POPULATION-SIZE-1.pdf