Produced by the chloroplast
Answer:

Explanation:
We want to find the density. The formula is mass over volume.

The mass is 500 kilograms. The volume is 0.026 cubic meters.

Substitute the values into the formula.

Divide.

This is just about equal to 19,320 kg/m³, so choice A is correct.
10.3 g of
will produce from 12.7 g
.
In simple terms, a limiting reagent is a reactant that is completely used up in the reaction.
It is also referred to as a limiting reactant or limiting agent.
Now, according to the question,
Since it is a limiting reagent, it will react fully.
The mass of
that will be produced will be:-
Equivalent mole of
= Equivalent weight of
= 12.7/169.97 = x*2/274x = 10.3 g.
Hence, 10.3 g of
will be produced.
It is used to restrict the reaction.
It tells you the estimated amount of compound to be used.
It brings quantitative understanding to chemical reactions.
More information on limiting reagents can be found here :
brainly.com/question/11848702
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<span>Answer: HgNO₃
</span><span />
<span>Explanation:
</span>
<span /><span /><span>
The empirical formula is the formula that shows the ratio of the atoms in its simplest form, this is using the smallest whole numbers.
</span><span />
<span>The empirical formula may or may not be the same molecular formula.
</span><span />
<span>In this case you are given the molecular formula Hg₂(NO₃)₂. Since, the ratio of the atoms of Hg, N, and O is 2: 2: 6, respectively, the same ratio is expressed if you divide by the greatest common factor (GCF).
</span><span>
</span><span>
</span><span>The GCF of 2, 2, and 6 is 2. So, the ratios can be simplified to 1:1:3, meaning 1 mol of Hg, 1 mol of N, and 3 mol of O or HgNO₃.</span>
Answer:
That the isotope H-1 is the most abundant in nature.
Explanation:
Hello!
In this case, since the average atomic mass of an element is computed considering the mass of each isotope and the percent abundance each, for hydrogen we would set up something like this:

Moreover, since the isotope notation H-1 and H-2 means that the atomic mass of H-1 is 1 amu, that of H-2 is 2 amu and the average one is 1.0079 amu, we can infer that the most of the hydrogen in nature is H-1 as the most of it composes the average hydrogen atom.
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