1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serga [27]
2 years ago
13

Six Carnot engines operating between different hot and cold reservoirs are described below. The heat energy transferred to the g

as during the isothermal expansion phase of each cycle is indicated.
Chemistry
1 answer:
Alla [95]2 years ago
7 0

Answer:

<u>Part -A</u>

The change in the entropy from largest to smallest is 3>2=4 >1 >5>6.

<u>Part-B</u>

Change in entropy over a complete cycle is 1 =2 = 3= 4  = 5 = 6

Explanation:

<u>Part -A</u>

The change in entropy for the reversible process that transfers the heat energy 'Q' at temperature 'T' is

\Delta S = \frac{Q}{T}

1)

\Delta S_{1} = \frac{Q}{T}

= \frac{1000J}{600K}= 1.67J/K

2)

\Delta S_{2} = \frac{Q}{T}

= \frac{1000J}{500K}= 2J/K

3)

\Delta S_{3} = \frac{Q}{T}

= \frac{1500J}{600K}= 2.5J/K

4)

\Delta S_{4} = \frac{Q}{T}

= \frac{1000J}{500K}= 2J/K

5)

\Delta S_{5} = \frac{Q}{T}

= \frac{500J}{500K}= 1J/K

6)

\Delta S_{6} = \frac{Q}{T}

= \frac{500J}{600K}= 0.83J/K

Therefore, The change in the entropy from largest to smallest is 3>2=4 >1 >5>6.

<u>Part-B</u>

\Delta S = \frac{Q}{T}

Q_{system}=work\,\,done

Initial and final states of complete cycle are equal. after complete the one cycle the system returns to the original state. So, the change in the entropy will be the zero

Therefore, Change in the overall cycle is 1 =2 = 3= 4  =5=6

You might be interested in
When PCl5 solidifies it forms PCl4+ cations and PCl6– anions. According to valence bond theory,
rewona [7]

Hey there!

No of hybrid orbitals , H = ( V +S - C + A ) / 2

Where H = no . of hybrid orbitals

V = Valence of the central atom = 5

S = No . of single valency atoms = 4

C = No . of cations = 1

A = No . of anions = 0

For PCl4 +

Plug the values we get H = ( 5+4-1+0) / 2

H =  4 ---> sp3 hybridization

sp3 hybrid orbitals are used by phosphorous in the PCl4+ cations

Answer C

Hope that helps!

3 0
3 years ago
Determine the number of bonding electrons and the number of nonbonding electrons in the structure of SI2. Enter the number of bo
mariarad [96]

Answer:

4, 16,

Explanation:

SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).

Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.

7 0
3 years ago
In ocean water, salt is a(n) _____.<br><br> a. solution<br> b. alloy<br> c. solvent<br> d. solute
stepan [7]
The answer is a. solution :)
3 0
3 years ago
Read 2 more answers
How many grams of calcium phosphate (Ca3(PO4)2) re theoretically produced if we start with 3.40 moles of Ca(NO3)2 and 2.40moles
sattari [20]

1) Balance the chemical equation.

3Ca(NO_3)_2+2Li_3PO_4\rightarrow6LiNO_3+Ca_3(PO_4)_2

2) List the known and unknown quantities.

Reactant 1: Ca(NO3)2.

Amount of substance: 3.40 mol.

Reactant 2: Li3PO4.

Amount of substance: 2.40 mol.

Product: Ca3(PO4)2

Mass: unknown.

3) Which is the limiting reactant?

<em>3.1-How many moles of Li3PO4 do we need to use all of the Ca(NO3)2?</em>

The molar ratio between Li3PO4 and Ca(NO3)2 is 2 mol Li3PO4: 3 mol Ca(NO3)2.

mol\text{ }Li_3PO_4=3.40\text{ }mol\text{ }Ca(NO_3)_2*\frac{2\text{ }mol\text{ }Li_3PO_4}{3\text{ }mol\text{ }Ca(NO_3)_2}=2.2667\text{ }mol\text{ }Li_3PO_4

<em>We need 2.2667 mol Li3PO4 and we have 2.40 mol Li3PO4. We have enough Li3PO4. </em>This is the excess reactant.

<em>3.2-How many moles of Ca(NO3)2 do we need to use all of the Li3PO4?</em>

The molar ratio between Li3PO4 and Ca(NO3)2 is 2 mol Li3PO4: 3 mol Ca(NO3)2.

mol\text{ }Ca(NO_3)_2=2.40\text{ }mol\text{ }Li_3PO_4*\frac{3\text{ }mol\text{ }Ca(NO_3)_2}{2\text{ }mol\text{ }Li_3PO_4}=3.60\text{ }mol\text{ }Ca(NO_3)_2

<em>We need 3.60 mol Ca(NO3)2 and we have 3.40 mol Ca(NO3)2. We do not have enough Ca(NO3)2. </em>This is the limiting reactant.

4) Moles of Ca3(PO4)2 produced from the limiting reactant.

We have 3.40 mol Ca(NO3)2 of the limiting reactant.

The molar ratio between Ca(NO3)2 and Ca3(PO4)2 is 3 mol Ca(NO3)2: 1 mol Ca3(PO4)2.

mol\text{ }Ca_3(PO_4)_2=3.40\text{ }mol\text{ }Ca(NO_3)_2*\frac{1\text{ }mol\text{ }Ca_3(PO_4)_2}{3\text{ }mol\text{ }Ca(NO_3)_2}=1.1313\text{ }mol\text{ }Ca_3(PO_4)_2

5) Mass of Ca3(PO4)2 produced.

The molar mass of Ca3(PO4)2 is 310.1767 g/mol.

g\text{ }Ca_3(PO_4)_2=1.1333\text{ }mol\text{ }Ca_3(PO_4)_2*\frac{310.1767\text{ }g\text{ }Ca_3(PO_4)_2}{1\text{ }mol\text{ }Ca_3(PO_4)_2}g\text{ }Ca_3(PO_4)_2=351.526\text{ }g\text{ }Ca_3(PO_4)_2

<em>The mass of Ca3(PO4)2 produced is</em> 351 g Ca3(PO4)2.

Option D.

.

8 0
1 year ago
The refrigerator has no room to cool the meat you've just cooked you should
stealth61 [152]
If the refrigerator has no room to cool the meat that you've just cooked, then you should clear it with other stuff or food that has not been consumed for days. There might be some goods that are not good for consumption anymore even though it has been placed in the ref for a couple of days. Hope this answers your question.
7 0
3 years ago
Other questions:
  • Which of these plants is cassini currently orbiting
    6·1 answer
  • A) Which of the following reagents would oxidize Cr to Cr2 , but not Fe to Fe3 ?
    5·1 answer
  • Question 7 of 32
    14·2 answers
  • 38 POINTS - PEER COUNSELING 2 QUESTION
    6·2 answers
  • 4. If 175 undecayed nuclei remain from a sample of 2800 nuclei, how many half-
    9·1 answer
  • You start with 100mL of 14M HNO3 and 10grams of copper metal. How many moles of the nitrogen dioxide gas will be produced?
    12·1 answer
  • Need answer now! 100 points
    11·2 answers
  • HURRY ! Kumar is producing the photoelectric effect by using red light. He wants to increase the energy of emitted electrons. Ba
    10·1 answer
  • Which coefficients correctly balance the formula equation below? NH 4 NO 2 (s) N 2 (g)+H 2 O(l) A. 1, 2, 2 C. B. 2, 1, 2 D. 1, 2
    7·1 answer
  • Look at Table 4 in the procedure portion of the experiment. Calculate the pH you would expect each of the buffer solutions (A, B
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!