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morpeh [17]
3 years ago
8

Given the equation representing a system at equilibrium:Which statement describes the concentration of the two gases in this sys

tem?The concentration of N2O4(g) must be less than the concentration of NO2(g).The concentration of N2O4(g) must be greater than the concentration of NO2(g).The concentration of N2O4(g) and the concentration of NO2(g) must be equal.The concentration of N2O4(g) and the concentration of NO2(g) must be constant.
Chemistry
1 answer:
WARRIOR [948]3 years ago
8 0

Answer:

.The concentration of N2O4(g) and the concentration of NO2(g) must be constant.

Explanation:

N2O4(g)<--------> 2NO2(g)

At equilibrium, all the concentrations of species involved in the equilibrium expression remain constant. This is because, at equilibrium, the rate of forward reaction equals the rate of reverse reaction. The concentration of the system does not change with time. The relative concentration of each specie, remain steady at equilibrium.

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What is Bose Einstein state of matter and their examples
Valentin [98]

Answer:

A BEC ( Bose - Einstein condensate ) is a state of matter of a dilute gas of bosons cooled to temperatures very close to absolute zero is called BEC.

Examples - Superconductors and superfluids are the two examples of BEC.

Explanation:

8 0
3 years ago
At 500K, the equilibrium constant for the reaction N2O4D2NO2 is 1.5 x 10^3. What is the equilibrium constant for the reaction: 6
Veronika [31]

Answer:

K = 2.96x10⁻¹⁰

Explanation:

Based on the initial reaction:

N2O4 ⇄ 2NO2; K = 1.5x10³

Using Hess's law, we can multiply this reaction changing K:

3 times this reaction:

3N2O4 ⇄ 6NO2; K = (1.5x10³)³ =3.375x10⁹

The inverse reaction has a K of:

6NO2 ⇄ 3N2O4 K = 1/3.375x10⁹;

<h3>K = 2.96x10⁻¹⁰</h3>

3 0
3 years ago
Career in chemistry list ten<br>​
romanna [79]

Explanation:

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3 0
3 years ago
Read 2 more answers
The isotope 90_Sr has a half-life of 28.8 years. What is the activity, measured in atoms/second of a 50 mg sample of "Sr? (10 pt
blsea [12.9K]

Answer:

2.5523\times 10^{11} atoms/secondsis the activity, measured in of a 50 mg sample of 90-Sr.

Explanation:

Half life of the 90-Sr ,t_{1/2}= 28.8 years

Activity coefficient of the 90-Sr = \lambda

\lambda =\frac{0.693}{28.8 years}=0.0240625 year^{-1}

Mass of 90-Sr = 50 mg = 0.050 g

Molecular mass of 90-Sr = 90 g/mol

Moles of 90-Sr =\frac{0.050 g}{90 g/mol}=0.0005555 mol

Number of atom in 0.0005555 moles of 90-Sr:

0.0005555 mol\times 6.022\times 10^{23} mol^{-1}=3.3455\times 10^{20} atoms

\lambda =0.0240625 year^{-1}=\frac{0.0240625}{3.154\times 10^7 s}=7.6292\times 10^{-10} s^{-1}

1 year = 3.154\times 10^7 seconds

Activity measured in atoms per seconds:

= Number of atoms × \lambda

=3.3455\times 10^{20} atoms\times 7.6292\times 10^{-10} s^{-1}

=2.5523\times 10^{11} atoms/s

5 0
3 years ago
Sodium has an atomic number of 11 and has a net charge of 0. When sodium combines with chlorine, it has a net charge of +1. Why?
Mamont248 [21]

Answer: Option (A) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{1}.

In order to gain stability, sodium loses one electron and hence it forms a positive ion (Na^{+}).

Thus, we can conclude that when sodium combines with chlorine, it has a net charge of +1 because sodium loses a negative electron when forming chemical bonds.

5 0
3 years ago
Read 2 more answers
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