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Natali [406]
3 years ago
10

The solid product from reaction of sulfuric acid with sucrose is?

Chemistry
1 answer:
Mama L [17]3 years ago
6 0

\huge{\mathbb{\tt {QUESTION:}}}

The solid product from reaction of sulfuric acid with sucrose is?

\huge{\mathbb{\tt {ANSWER:}}}

  • Concentrated <u>sulfuric acid</u> is added to sucrose forming carbon, steam and <u>sulfur</u> dioxide.

<h2>--------------------------------------------------------------------------------</h2>

<h3>RELATED TO THE QUESTION </h3>

\huge{\mathbb{\tt {What \:  is \:  solid?:}}}

  • <u>Solid is one of the four fundamental states of matter</u>. The molecules in a solid are closely packed together and contain the least amount of kinetic energy.
  • <u>A solid is characterized by structural rigidity and resistance to a force applied to the surface</u>.

\huge{\mathbb{\tt {What \:  is \:  sulfur \:  acid?}}}

  • <u>Sulfuric acid or sulphuric acid, also known as oil of vitriol, is a mineral acid composed of the elements sulfur, oxygen and hydrogen</u>, with molecular formula H₂SO₄. It is a colorless, odorless and viscous liquid that is miscible with water at all concentrations.

\huge{\mathbb{\tt{What \:  is \:  sucrose?}}}

  • <u>Sucrose is common sugar. It is a disaccharide</u>, a molecule composed of two monosaccharides: glucose and fructose. Sucrose is produced naturally in plants, from which table sugar is refined. It has the molecular formula C₁₂H₂₂O₁₁.

#CarryOnLearning

#LetsEnjoyTheSummer

<h3>→XxKim02xX</h3>
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How are science and technology related
KatRina [158]

There is no answer, science is about empirical knowledge, technology is the sum of techniques, skills, methods, and processes. I do not believe that you will find a answer for that.

7 0
3 years ago
The arrangement of the elements from left to
maria [59]
It is bases on "Atomic number"

In short, Your Answer would be Option B

Hope this helps!
5 0
3 years ago
Read 2 more answers
A block of substance has a width of 3.8 cm, a length of 8.2 cm, and height of 7 cm . Its mass is 0.68 kg. Calculate the density
satela [25.4K]

Answer:

d = 3.11 g /cm³

Explanation:

Volume -

The volume of a cuboidal object can be calculated by multiplying the length , width and height ,

Hence , Volume ( V ) = l * w * h ,

From the question ,

l = 8.2 cm

w = 3.8 cm

h = 7 cm

Hence, the volume is ,

V = l * w * h

V = 8.2 cm * 3.8 cm * 7 cm

V = 218.12 cm³

Density -

Density of a substance is given as the mass divided by the volume ,

Hence,

d = m / V

From the question,

m = 0.68 kg

since ,

1 kg = 1000g

m = 0.68 * 1000 = 680 g

V = 218.12 cm³ ( calculated above )

Hence , the value of density can be calculated by using the above equation,

d = m / V

d = 680 g / 218.12 cm³

d = 3.11 g /cm³

8 0
3 years ago
The following list contains some common polyatomic ions. Using the charge on these ions and the idea of valence, predict the for
SSSSS [86.1K]

Answer: Na_2CO_3 or Sodium carbonate.

              KMnO_4 or Potassium permanganate

Sodium ion carries 1 + charge whereas carbonate ion carries overall charge of -2. So for every carbonate ion, two sodium ions combine to balance the charges and thus form a stable compound, Na_2CO_3

Potassium ion carries 1 + charge where as permanganate ion carries overall charge of -1. So for every permanganate ion, one potassium ion combines to balance the charges and thus form a stable compound,  KMnO_4

The predicted formulas are shown in the attached image.


5 0
3 years ago
Read 2 more answers
Chlorine has two isotopes, 35Cl and 37Cl that have the respective percent abundance's of 75.77% and 24.23% and masses of 34.9688
AnnyKZ [126]

Answer:

The answer to your question is  35.4527 g

Explanation:

Data

Cl-35    abundance = 75.77 %    mass Cl-35 = 34.9688

Cl-37     abundance = 24.23 %   mass Cl-37 = 36.9659

Process

1.- Convert the percents to decimals

   75.77% = 75.77/100 = 0.7577

   24.23% = 24.23/100 = 0.2423

2.- Find the atomic weight

    Average atomic weight = Abundance 1 x Mass Cl-35 +

                                               Abundance 2 x Mass Cl-37

Substitution

     Average atomic weight = (0.7577)(34.9688) + (0.2423 x 36.9659)

Simplification

     Average atomic weight = 26.4959 + 8.9568

Result

      Average atomic weight = 35.4527 g

3 0
3 years ago
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