There is no answer, science is about empirical knowledge, technology is the sum of techniques, skills, methods, and processes. I do not believe that you will find a answer for that.
It is bases on "Atomic number"
In short, Your Answer would be Option B
Hope this helps!
Answer:
d = 3.11 g /cm³
Explanation:
Volume -
The volume of a cuboidal object can be calculated by multiplying the length , width and height ,
Hence , Volume ( V ) = l * w * h ,
From the question ,
l = 8.2 cm
w = 3.8 cm
h = 7 cm
Hence, the volume is ,
V = l * w * h
V = 8.2 cm * 3.8 cm * 7 cm
V = 218.12 cm³
Density -
Density of a substance is given as the mass divided by the volume ,
Hence,
d = m / V
From the question,
m = 0.68 kg
since ,
1 kg = 1000g
m = 0.68 * 1000 = 680 g
V = 218.12 cm³ ( calculated above )
Hence , the value of density can be calculated by using the above equation,
d = m / V
d = 680 g / 218.12 cm³
d = 3.11 g /cm³
Answer:
or Sodium carbonate.
or Potassium permanganate
Sodium ion carries 1 + charge whereas carbonate ion carries overall charge of -2. So for every carbonate ion, two sodium ions combine to balance the charges and thus form a stable compound, 
Potassium ion carries 1 + charge where as permanganate ion carries overall charge of -1. So for every permanganate ion, one potassium ion combines to balance the charges and thus form a stable compound, 
The predicted formulas are shown in the attached image.
Answer:
The answer to your question is 35.4527 g
Explanation:
Data
Cl-35 abundance = 75.77 % mass Cl-35 = 34.9688
Cl-37 abundance = 24.23 % mass Cl-37 = 36.9659
Process
1.- Convert the percents to decimals
75.77% = 75.77/100 = 0.7577
24.23% = 24.23/100 = 0.2423
2.- Find the atomic weight
Average atomic weight = Abundance 1 x Mass Cl-35 +
Abundance 2 x Mass Cl-37
Substitution
Average atomic weight = (0.7577)(34.9688) + (0.2423 x 36.9659)
Simplification
Average atomic weight = 26.4959 + 8.9568
Result
Average atomic weight = 35.4527 g