$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL$

Putting values in above equation, we get:

$0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g$

Hence, the mass of glucose in final solution is 1.085 grams

4 0

3 years ago

At which electrade in a voltaic cell does redaction always occar?

yanalaym [24]

Answer:cathode

Explanation:It is also known as the galvanic cell or electrochemical cell. In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

7 0

3 years ago

how many moles of iron will be produced from 6.20 moles of carbon monoxide reacting with excess iron (III) oxide (FeO3) to produ

Gelneren [198K]

0.20 moles of iron will be formed in the reaction.

Explanation:

The balanced chemical equation for the reaction between iron (iii) oxide and carbon monoxide to form Fe is to be known first.

the balanced reaction is :

Fe2O3 + 3CO⇒ 2 Fe + 3 CO2

so from the data given the number of moles of carbon monoxide can be known:

3 moles of CO reacted with Fe2O3 to form 2 moles of iron in the reaction.

Number of moles of CO is 6.20 moles

11.6 gm of iron is formed

so the number of moles of iron formed is calculated as

n = mass of iron ÷ atomic weight of iron

= 11.6 ÷ 55.84

= 0.20 moles of iron will be formed when 11.6 gram of iron is produced.

5 0

3 years ago