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2 years ago

PLS HELP! I NEED THIS!!!!

Chemistry

2 answers:

masha68 [24]2 years ago

7 0

I’m sure it’s 6 km/h south

Kazeer [188]2 years ago

3 0

I believe it’s 6km/ south

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A compound has a molar mass of 44.01 g/mol. What is its identity?

Bess [88]

This problem is very vague since no other details are given. However for the sake of calculation let us assume that the compound is an ideal gas at STP.

So that the molar volume is: 1 mole = 22.4 L

<span>density = (44.01 g/mol) * (1 mol / 22.4 L) = 1.96 g/L = 1.96 kg/m^3</span>

6 0

2 years ago

Charlie measures the mass of a metal three times and recorded 8.83 g,

Marina CMI [18]

Answer:what’s the answer

Explanation:

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3 years ago

The ksp of manganese(ii) carbonate, mnco3, is 2.42 × 10-11. calculate the solubility of this compound in g/l.

Vikki [24]

Answer : The solubility of this compound in g/L is $565.414\times 10^{-6}g/L$ .

Solution : Given,

$K_{sp}=2.42\times 10^{-11}$

Molar mass of $MnCO_3$ = 114.945g/mole

The balanced equilibrium reaction is,

$MnCO_3\rightleftharpoons Mn^{2+}+CO^{2-}_3$

At equilibrium s s

The expression for solubility constant is,

$K_{sp}=[Mn^{2+}][CO^{2-}_3]$

Now put the given values in this expression, we get

$2.42\times 10^{-11}=(s)(s)\\2.42\times 10^{-11}=s^2\\s=0.4919\times 10^{-5}=4.919\times 10^{-6}moles/L$

The value of 's' is the molar concentration of manganese ion and carbonate ion.

Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.

$s=4.919\times 10^{-6}moles/L\times 114.945g/mole=565.414\times 10^{-6}g/L$

Therefore, the solubility of this compound in g/L is $565.414\times 10^{-6}g/L$ .

8 0

2 years ago

Substituents on an aromatic ring can have several effects on electrophilic aromatic substitution reactions. Substituents can act

Leya [2.2K]

Answer:

Option A=> -NHCOCH3 and option C = -CH3.

Explanation:

The option A that is -NHCOCH3 is CORRECT because it possesses lone pair of electron with the exception of group 7A elements. It is this lone pair that is used in the Activation of the ring towards substitution. Other groups that falls into this group are; OCH3, alkyls and many others.

Option B that is -COOH is good group for withdrawal of electron through Resonance. Other examples are NO2, -CN and SO3H.

Option C falls to the same category as option A above that is Activation of the ring towards substitution.

Option D falls to the same category as option B above that is group for withdrawal of electron through Resonance.

7 0

3 years ago

How many mm are in 38,987 L?

OlgaM077 [116]

Answer:

38987000

Explanation:

there are 1000 ml in a Liter.

Hope this helps!

6 0

2 years ago