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attashe74 [19]
3 years ago
12

What are the energy in a plant?

Chemistry
1 answer:
Vadim26 [7]3 years ago
3 0
In plants, these energy factories are called chloroplasts. They collect energy from the sun and use carbon dioxide and water in the process called photosynthesis to produce sugars. Animals can make use of the sugars provided by the plants in their own cellular energy factories, the mitochondria.
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The following reaction is exothermic.
earnstyle [38]

Answer : The correct option is, (C) spontaneous only at low temperatures.

Explanation :

According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy  

\Delta H = enthalpy change

\Delta S = entropy change  

T = temperature in Kelvin

As we know that:

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

The given chemical reaction is:

2S(s)+3O_2(g)\rightarrow 2SO_3(g)

As we are given that, the given reaction is exothermic that means the enthalpy change is negative.

In this reaction, the randomness of reactant molecules are more and as we move towards the formation of product the randomness become less that means the degree of disorderedness decreases. So, the entropy will also decreases that means the change in entropy is negative.

Now we have to determine the spontaneity of this reaction when ΔH is negative and ΔS is negative.

As, \Delta G=\Delta H-T\Delta S

\Delta G=(-ve)-T(-ve)

\Delta G=(+ve)   (at high temperature) (non-spontaneous)

\Delta G=(-ve)   (at low temperature) (spontaneous)

Thus, the reaction is spontaneous only at low temperatures.

4 0
3 years ago
A fuel gas containing 86% methane, 8% ethane, and 6% propane by volume flows to a furnace at a rate of 1450 m3/h at 15°C and 150
Svetach [21]

Answer:

Basis: Hour

From the question, we will have the following reactions;

CH4 + 2O2   -------- CO2 + 2H20   (Methane with O2)

C2H6 + 3.5O2  -------- 2CO2 + 2H2O  (Butane with O2)

C3H8 + 5O2   ---------- 2CO2 + 4H2O   (Propane with O2)

But we are also given this,

R=8.314J/mol.K, V=1450m3/h, P=150kPa gauge, Pt=150+101kPa=251kPa, T=15C= 288K

Assuming they are all ideal gases, we can find the no of moles of the gases.

n=PV/RT,

n = 251x103 x 1450 /8.314 x 288

n = 151, 999mols = 152kmols

However from the input and complete reactions stoichiometries above, we will have,

1.  Methane 86% = 0.86 x 152kmols = 130kmols, required O2 = 2 x 130.7 = 261.44kmols

2. Ethane 8% = 0.08 x 152kmols = 12.2kmols, required O2 = 3.5 x 12.2 = 42.56kmols

3. Propane 6% = 0.06 x 152 kmols = 9.2kmols, required O2 = 5 x 9.1 = 45.5kmols

O2 = 349.5kmols,  with 8% excess, Total O2 = 349.5+ (0.08x349.5) = 377.46kmols

But Air:O2 = 21%: 100%

inflow Air = 377.46x 100/21= 1797.5kmols, at standard pressure and temperature.

From PV =nRT

V (M3/H) = nRT/P

 =====  1797.5mol x 8.314Nm/mol.K x 273K/101325Nm-2 x 1000

Hence, the required flow rate of air in SCMH = 40,265m³/h

3 0
3 years ago
The Resource Conservation and Recovery Act controls hazardous waste from its creation to its disposal. Please select the best an
o-na [289]

Answer:

True

Explanation:

Resource Conservation and Recovery Act (RCRA). 1976 of United States Environmental Protection Agency(EPA) empowers EPA to control the production, transportation, storage, treatment and disposal of hazardous waste. The RCRA act was amended in 1984 and 1986 to include Waste minimization along with appropriate disposal (not in the landfill site) and tackling of petroleum hazardous waste respectively along with other waste.

7 0
3 years ago
Read 2 more answers
How many per tickets are in one mole?
Alexeev081 [22]

Answer:

Avogadro's number is a proportion that relates molar mass on an atomic scale to physical mass on a human scale. Avogadro's number is defined as the number of elementary particles (molecules, atoms, compounds, etc.) per mole of a substance. It is equal to 6.022×1023 mol-1 and is expressed as the symbol NA.

Explanation:

7 0
3 years ago
Sub-groups on periodic table
marissa [1.9K]

Answer:

Subgroups S, P, D, F, including elements of blocks s, p, d, f, respectively.

<h2><em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you</u></em><em><u>✨</u></em><em><u>.</u></em><em><u> </u></em></h2>

<em><u>Thanks</u></em><em><u>☸</u></em><em><u>.</u></em><em><u> </u></em>

4 0
3 years ago
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