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Hitman42 [59]
3 years ago
6

A student is adding DI water to a volumetric flask to make a 50% solution. Unfortunately, he was not paying attention and filled

the flask past the calibration mark. Instead of starting over, the student decides to continue with the experiment. How will the student's results be affected by his mistakes
Chemistry
1 answer:
dalvyx [7]3 years ago
4 0

Answer:

His results will be skewed because there was more water than stock solution. Which would cause the percentage solution to be less than 50% therefore the density would be less than the actual value.

Explanation:

The solution will have percentage less than that of 50%. Therefore the density would be less than the actual value.

Suppose there should be 50 mL of the solution, and he added 60 mL. So 10 mL of the solution is added more.

Suppose the mass of the solute is m.

Originally, the density is = $\frac{m}{50}$     \left(\frac{\text{mass}}{\text{volume}}\right)

Now after adding extra 10 mL , the density becomes $\frac{m}{60}$.

Therefore, $\frac{m}{50}>\frac{m}{60}$

So the density decreases when we add more solution.

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Aspirin can be prepared from salicylic acid ( C 7 H 6 O 3 CX7HX6OX3), which has a molar mass of 138.12 g/mol, and acetic anhydri
pychu [463]

Answer: The theoretical yield of aspirin is 4.14 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of salicylic acid}=\frac{3.20g}{138.12g/mol}=0.023moles

mass of acetic anhydride = density\times volume =1.082g/ml\times 3.71ml=4.01g

\text{Moles of acetic anhydride}=\frac{4.01g}{102.04g/mol}=0.039moles

C_9H_6O_3+C_4H_6O_3\rightarrow C_9H_8O_4+C_2H_3O_2  

According to stoichiometry :

1 mole of salycylic acid require 1 mole of acetic anhydride

Thus 0.023 moles of  salycylic acid require=\frac{1}{1}\times 0.023=0.023moles  of acetic anhydride

Thus salycylic acid is the limiting reagent as it limits the formation of product and acetic anhydride is the excess reagent.

As 1 mole of salycylic give = 1 mole of aspirin

Thus 0.023 moles of salycylic acid give =\frac{1}{1}\times 0.023=0.023moles  of aspirin

Mass of aspirin = moles\times {\text {Molar mass}}=0.023moles\times 180.15g/mol=4.14g

Thus theoretical yield of aspirin is 4.14 g

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