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Maru [420]
3 years ago
10

9. In Millikan's oil drop experiment an oil

Physics
1 answer:
Sloan [31]3 years ago
6 0
From the figure, F
e
​
and F
g
​
represents electric and gravitational forces respectively.
We can observe that,

V∝
q
m
​


and in turn m∝r
3

given V = 400V is initial voltage and let V
1
​

substituting these values in the respective equations we get

V
V
1
​

​
=
r
3
(q)
(2r)
3
q
​


solving the above eqaution will give us
V
1
​
=8×V=3200 V
So, the answer is option (C).
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A small spaceship with a mass of only 2.8 ✕ 103 kg (including an astronaut) is drifting in outer space with negligible gravitati
Luda [366]

Answer:

962.14m/s

Explanation:

Data obtained from the question include:

m (mass) = 2.8x10^3 kg

P (power) = 30 kW = 30 x 1000 = 30000W

V (velocity) =?

t (time) = 1 day

There are 24 hours in a day.

t (time) = 1 day = 24 hours

We need to covert 24 hours to seconds. This is illustrated below:

There are 60 minutes in 1 hour and 60 seconds in 1 minutes.

Therefore, 24hours = 24 x 60 x 60 = 86400 seconds.

t (time) = 1 day = 24 hours = 86400 seconds

Power is related to velocity according to equation:

Power = force x Velocity

P = F x v (1)

Recall Force (F) = Mass (m) x a (acceleration) i.e F = ma

Substituting the value of F into equation 1, we have:

P = F x v

P = ma x v

P = m x a x v (2)

But: acceleration (a) = Velocity(v)/time(t) i.e a = v/t

Substituting the value of a into equation 2, have:

P = m x a x v

P = m x v/t x v

P = (m x v^2)/ t

Now, with this equation

P = (m x v^2)/ t, we can obtain the speed of the spaceship as follow:

P = (m x v^2)/ t

30000 = (2.8x10^3 x v^2) /86400

Cross multiply to express in linear form

2.8x10^3 x v^2 = 30000 x 86400

Divide both side by 2.8x10^3

v^2 = (30000 x 86400)/ 2.8x10^3

v^2 = 925714.2857

Take the square root of both side

v = √(925714.2857)

v = 962.14m/s

Therefore, the speed of the spaceship is 962.14m/s

3 0
3 years ago
Read 2 more answers
A .71-kg billiard ball moving at 2.5 m/s in the x-direction strikes a stationary ball of the same mass. After the collision, the
Finger [1]

After the collision, the momentum didn't change, so the total momentum in x and y are the same as the initial.

The x component was calculated by subtracting the initial momentum (total) minus the momentum of the first ball after the collision

In the y component, as at the beginning, the total momentum was 0 in this axis, the sum of both the first and struck ball has to be the same in opposite directions. In other words, both have the same magnitude but in opposite directions

\begin{gathered} Py=0.71kg\cdot2.17\cdot sin(30) \\ Py=0.77kg\cdot m/s \end{gathered}

This is for both balls after the collision, but one goes in a positive and the other in a negative direction.

7 0
1 year ago
In 1967, new zealander burt munro set the world record for an indian motorcycle, on the bonneville salt flats in utah, with a ma
Fed [463]
Draw a velocity-time diagram as shown below.

Because a velocity of 26.82 m/s is attained in 4.00 s from rest, the average acceleration is
a = 26.82/4 = 6.705 m/s²
The time required to reach maximum velocity of 82.1 m/s is
t₁ = (82.1 m/s)/(6.705 m/s²) = 12.2446 s

The distance traveled during the acceleration phase is
s₁ = (1/2)at₁²
    = (1/2)*(6.705 m/s²)*(12.2446 s)²
    = 502.64 m

Answer:
The time required to reach maximum speed is 12.245 s
The distance traveled during the acceleration phase is 502.6 m

3 0
3 years ago
A major league pitcher can throw a baseball with a kinetic energy of 150 J. How much work must the pitcher do to the ball to giv
kenny6666 [7]

Answer:

A= 150 J

Explanation:

Kinetic energy is the energy of an object in motion.

The formula for kinetic energy is ;

K.E = 1/2 * m *v²  where m is mass and v is velocity

Work done is equal to change in kinetic energy

W= Δ K.E

Given that K.E = 150 J

Taking that the ball was stationary before it was thrown, this makes its initial kinetic energy to be 0 J so the work done will be

W=  Δ K.E

W= 150 - 0

W= 150 J

4 0
3 years ago
Which statement is true about the turbine in a hydroelectric dam? a. It is turned by wind and provides a direct current. b. It i
tresset_1 [31]
B) It is turned by water to produce a direct current....... hope it helps :)
8 0
3 years ago
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