Y = log x / x
y ` = (( log x )` * x - (x)` * log x) / x²=
= (1/x * x - 1 * log x ) / x² =
= ( 1 - log x ) / x²
y ` = 0;
1 - log x = 0
log x = 1
x = e
The maximum value:
y max = log e / e = 1 / e
<span>x^3 + 3.4y when x = 4 and y = 2
= 4^3 + 3.4 (2)
= 64 + 6.8
= 70.8
</span>
Diagram is attached. No, the relation is not a function.
In order for a relation to be a function, each input value must be mapped to no more than 1 output value. One of our input values, -2, is mapped to 2 output values (-1 and 0). Therefore this is not a function.
Answer:
Each witch is 15
Each broom is 7
Each spoon is 4
So when you take the broom and spoon off of the witch that makes the witch worth 4
Apply rules of math
So 4x7=28
4+28
32
Answer:
Step-by-step explanation: -1, 16