$\frac{4}{5} = 64 \\ \frac{1}{5} = 64 \div 4 \\ \: \: \: \: \: \: = 16 \\ total \: managers \: = 16 \times 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 80 \\ number \: of \: male \: \: managers \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{5}{5} - \frac{4}{5} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{5} = 16$

hope this helps you.

5 0

3 years ago

A submersible vessel at an elevation of -95 feet descends to 5 times that elevation. What is the vessel's new elevation?

trasher [3.6K]

-475
you multiply -95 by 5

6 0

4 years ago

X and Y are independent random variables. X is normally distributed with mean 1 and variance 1. Y is normally distributed with m

g100num [7]

Answer:

Step-by-step explanation:

Equation of variance:

Total Variance = sum (i=1, N) {c^2,variance^2}

= c1^2*variance1^2 + c2^2*variance2^2 + .....

Variance of X = 1

Variance of Y = 5

Variance of Y - 2X = (1^2)*(5) - (2^2)**(1)

= 5 - 4 = 1

8 0

3 years ago