So firstly, multiply both sides by t: 
Next, add both sides by v0, and your answer will be: 
Area of a square:
A= side^2
= (6x + 1) ^2
=<u> 36x^2 + 12x + 1 feet^2</u>
Answer:
We are given that angle AOB is a central angle of circle O and that angle ACB is a circumscribed angle of circle O. We see that AO ≅ BO because
✔ all radii of the same circle are congruent.
We also know that AC ≅ BC since
✔ tangents to a circle that intersect are congruent.
Using the reflexive property, we see that
✔ side CO is congruent to side CO.
Therefore, we conclude that △ACO is congruent to △BCO by the
✔ SSS congruence theorem.
please mark brainliest.... hope you have a great day ! XD
Im pretty sure its 58. your welcome
<h3>
Exact Area = 1200 - 300pi square cm</h3><h3>
Approximate Area = 257.522203923062 square cm</h3>
Work Shown:
The area of the rectangle is 40*30 = 1200 square cm
Note how we have 4 circles along the horizontal dimension which is 40 cm, so each diameter is 40/4 = 10 cm, and the radius is 10/2 = 5 cm
Each circle has an area of pi*r^2 = pi*5^2 = 25pi
There are 4*3 = 12 circles, so the circle areas combine to 12*25pi = 300pi
Using a calculator, we find that 1200 - 300pi = 257.522203923062 approximately. Round this however you need to.
