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Alex777 [14]
3 years ago
7

Power usage is measured in kilowatt-hours, kWh. After 7 a.m., the power usage on a college campus increases at a rate of 21% per

hour. Prior to 7 a.m., 15,040 kWh have been used. The university has a daily goal to keep their power usage less than or equal to 100,000 kWh.
Which of the following inequalities can be used to determine the number of hours, t, after 7 a.m. when the power usage on campus will be less than or equal to 100,000?A.
15,040(0.79)t ≤ 100,000
B.
15,040(1.79)t ≤ 100,000
C.
15,040(1.021)t ≤ 100,000
D.
15,040(1.21)t ≤ 100,000
Mathematics
1 answer:
ivann1987 [24]3 years ago
3 0

Answer:

D. 15,040(1.21)t ≤ 100,000

Step-by-step explanation:

The 15,040 is the prior electricity, and it increases by .21 per hour, and you don't want 100,000

To make an equation, use the simple interest formula (same concept)

Total = Amount(1 + rate) time

fill it out

100,000 >= 15,040(1.21)t

This equation is the same as D so D is the answer

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SinA=√1-x÷√1+X<br> Find the value of cosA
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The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

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Then,

opposite = \sqrt{1} - x

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2 years ago
Endpoint: (1,7), midpoint: (-10,10)
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This gives us the final point of (-21, 13)

5 0
3 years ago
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