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motikmotik
3 years ago
11

If the measurement of Angle 6 = 50 degrees, then the measurement of Angle 3 = 50 degrees

Mathematics
2 answers:
olga_2 [115]3 years ago
4 0

Answer:

True

Step-by-step explanation:

angle 3 and 6 are alternate angles.

alternate angles have the following characteristics:

1. they are inside the parallel lines

2. they are on opposite sides of the transversal

3. they are EQUAL

another example of alternate angles is angle 4 and angle 5

Marta_Voda [28]3 years ago
4 0

Answer:

True

Step-by-step explanation:

I took this in my class already

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6 - 8x = 5x - 10x + 12<br> Please help I suck at math thank you
Irina18 [472]

Answer:

I guess it's -2

Step-by-step explanation:

6-8x = 5x - 10x + 12

∴ 10x - 8x - 5x = 12 - 6

∴ 10x- 13x = 6

∴ - 3x = 6

∴ x = -6\3

∴ x = -2

3 0
2 years ago
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Which of the following represents the rate of change for a linear function
kolbaska11 [484]

Answer:

the Answer is (B) change in y/ change in x

Step-by-step explanation:

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4 0
3 years ago
Please help me with this problem!!
Ghella [55]
It’s 2 times the variable
4 0
3 years ago
The point (5, -2) is rotated 90° about the origin. Its image is
tigry1 [53]
<span>rotated 90° about the origin
(x,y) = (-y, x)

so </span><span>(5, -2) is rotated 90° about the origin = (2, 5)

answer
</span><span>b.(2, 5)</span>
7 0
3 years ago
X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

7 0
3 years ago
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