Answer:
The statement H is the correct one: The number of atoms on the reactant side equals the number of atoms on the product side.
Explanation:
The law of conservation of mass states that mass can not be created or destroyed, just can be transformed. The mass of a system can not be added or removed, thereby the transfer of mass in a reaction must remain constant.
This implies that the mass of the molecules on the side of the reactants before the reaction must be equal to the mass of the atoms on the side of the products after the reaction.
Therefore, the statement H is the correct one: The number of atoms on the reactant side equals the number of atoms on the product side.
I hope it helps you!
Answer:
Velocity = 15.87m/s
Explanation:
Given the following data;
Distance, d = 200000m
Time, t = 12600secs
*To find the velocity*
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
Substituting into the equation, we have;
Velocity = 15.87m/s
<em>Therefore, the velocity of the car is 15.87 meters per seconds due west.</em>
Answer:
Explanation:
Given that
F=ax^3/2. a is a constant
The force does a work of
W=2.01KJ from x=0 to x=15.2m
We need to find a
Work is give as,
W=∫F.ds
But this is in x direction only then,
W=∫Fdx. from x=0 to x=15.2m
W=∫ax^3/2dx from x=0 to x=15.2m
W=ax^(3/2+1)/(3/2+1).
W=ax^(5/2)/5/2
W=ax^(2/5)/2.5 from x=0 to x=15.2m
Cross multiply
2.5W=ax^2.5. from x=0 to x=15.2m
2.5W= a (15.2^2.5-0)
W=2.01KJ=2010J
2.5×2010=a×900.76
Therefore,
a=5.56
The equation which shows the relationship between frequency, wavelength and velocity of particle is given as,
Here, f is the frequency, v is the velocity and
is the wavelength. The frequenc
Answer:
a) t =12[s]; b) x = 348[m]
Explanation:
We can solve this problem using the following kinematics equations:
a)
where:
vf = final velocity = 12 [m/s]
vo= initial velocity = 6 [m/s]
a = acceleration = 0.5[m/s^2]
t = time [s]
Now clearing the time t, we have:
b)
We can calculate the displacement for the first 12 [s] then using the equation for the constant velocity we can calculate the other displacement for the 20[s].
The we can calculate the second displacement for the constant velocity:
x = x1 + x2
x = 108 + 240
x = 348[m]