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galina1969 [7]
3 years ago
15

When is the universal theme of a story often revealed?

Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0
It is often revealed <span>at the resolution of the story, when the reader can see how the story ends.</span>
kap26 [50]3 years ago
6 0

Answer:

I'm stuck on the same one

Explanation:

I'm not sure

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Scientists can help us understand the impact of human activities on the environment. True or false?
zhannawk [14.2K]

Answer:

True

Explanation:

hope it will help you

5 0
2 years ago
Amadeo the Archer is practicing his archery skills. He shoots both arrows into a field. His first arrow (arrow A) is embedded ha
attashe74 [19]

Answer:

1

The arrow with greater impart is Arrow B

2

The both arrows will feel the same impulse

Explanation:

1. Arrow B since KE= W = F * d  it used more force to stop itself in a shorter distance.

2. They should feel the same impulse since the both had the same momentum    m * v= F * t

4 0
3 years ago
A 65.0 kg ice skater standing on frictionless ice throws a 0.15 kg snowball horizontally at a speed of 32.0 m/s. What is the vel
spin [16.1K]

Answer:

(d) 0.07 m/s

Explanation:

Given Data

Snowball mass m₁=0.15 kg

Ice skater mass m₂=65.0 kg

Snowball velocity v₁=32.0 m/s

To find

Velocity of Skater v₂=?

Solution

From law of conservation of momentum

m_{1}v_{1}=m_{2}v_{2}\\  v_{2}=\frac{m_{1}v_{1}}{m_{2}}\\ v_{2}=\frac{(0.15kg)(32.0m/s)}{65.0kg}\\ v_{2}=0.0738m/s\\or\\v_{2}=0.07 m/s

So Option d is correct one

5 0
3 years ago
What change will most likely increase the strength of a magnetic field produced by an electromagnet? a. Reduce the number of tur
Anettt [7]

Answer:

Option D

Explanation:

When another battery is added to the circuit, the power supplied through the coil and to the magnet becomes greater leading to stronger magnetic field lines being produced.

7 0
4 years ago
The rest mass of a proton is 1.673 × 10-27 kg. The relativistic mass of a proton when its velocity is 0.8c is approximately
sergiy2304 [10]
Do u know the formula
m= \frac{ m_{0} }{ \sqrt{1- \frac{ v^{2} }{ c^{2} } } }
7 0
3 years ago
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