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katovenus [111]
2 years ago
11

Atomos neutros de um certo elemento representativo M apresentam dois elétrons em sua camada de valência. As fórmulas corretas pa

ra seu óxido normal e brometo são, respectivamente: (Dados: O = 6A e Br = 7A) a) M20 e MBr. B) MO2 e MBr2. C) MO e MBr2. D) M2O2 e M2Br.
Physics
1 answer:
fgiga [73]2 years ago
7 0

MO and  MBr₂

Explanation:

The compounds that would be formed are MO and MBr₂:

 Here is a simple approach to find them molecular formula of the compounds.

Every atom has combining power which illustrates the number of electrons usually lost, gained or shared by atoms of elements during chemical combinations.

    Species:

        M            2 valence electrons  to be lost

        O             2 valence electrons needed

        Br             1 valence electron needed

                                  M                               O

combining

powers                       2                                2

Exchange

of power                     2                                2

   Formula of compound         MO

                                   M                           Br

combining

powers                       2                            1

Exchange

of power                    1                             2  

                                               MBr₂

Learn more:

Molecular formula brainly.com/question/6125309

#learnwithBrainly

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If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu
zubka84 [21]

Answer:

minimum speed is 15.35 m/s

frictional coefficient  is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and   minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² =  236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 =  0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245  = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient  is 0.26

4 0
2 years ago
Read 2 more answers
How can understanding velocity help to prevent a mid-air collision
dsp73

Answer:

To maintain enough time to prevent a collision, a system operating in air traffic where aircraft speed does not

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2 years ago
Four seconds after being launched, what is the height of a ball that starts from a height of 12 m with an initial upward velocit
MrMuchimi

Answer:

15.24 m/s in the downward direction

Explanation:

Given that the initial upward velocity of the ball is 24 m/s.

Assuming that the upward direction is positive.

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Now, from the equation of motion, when an object is launched with initial velocity u, the final velocity, v, of an object after time t is v=u+at.

Given that u=24 m/s, t=4 seconds, g=-9.81 m/s^2.

So, the final velocity is

v= 24 + (-9.81)\times 4 \\\\\Rightarrow v= 24-9.81\times 4

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8 0
2 years ago
How long (in seconds) does it take a car accelerating at 3.1 m/s2 to go from rest<br> to 51 m/s?
Nesterboy [21]

Answer:

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Explanation:

Given parameters:

Acceleration = 3.1m/s²

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Unknown:

Time taken  = ?

Solution:

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u is the initial velocity

t is the time taken

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