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Deffense [45]
2 years ago
12

Please help. If this isn't done by today i'm grounded :(

Mathematics
2 answers:
Romashka [77]2 years ago
8 0

Answer:

B. temporary

 

Step-by-step explanation:

DedPeter [7]2 years ago
4 0

Answer:

B. temporary

Step-by-step explanation:

The last sentence says that the alignment of atoms does not last long.

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3. Jessie has 25 small
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500 rocks

Step-by-step explanation:

25*20 = 500

7 0
2 years ago
Asphere and a cylinder have the same radius and height. The volume of the cylinder is 18 cm3.
spin [16.1K]

Answer:

6

Step-by-step explanation: Hi the answer is 6 because a cylinder is 3 times a cone so the cylinder divided by 3 would be your answer

4 0
3 years ago
4. Timothy deposited $3500 into an accountthat pays 4.3% simple interest and keeps it
hjlf
$3,500(4.3%)4= $602

His new account balance after interest is $602
6 0
2 years ago
Find the maximum value or minimum value for the function f(x) = 0.15(x + 1)² - 3.
il63 [147K]

Answer:

The minimum value for  f(x) = 0.15(x + 1)^2 - 3 is -3.

Step-by-step explanation:

Given function is f(x) = 0.15(x + 1)^2 - 3

We need to find the maximum value or the minimum value for the function.

Now, differentiate f(x) = 0.15(x + 1)^2 - 3  w.r.t x.

f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\

f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)

Now, we will equate f'(x)=0 to find critical point.

0.3(x+1)=0\\x=-1

Plug this critical point in to the function f(x) = 0.15(x + 1)^2 - 3  we get,

f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3

Also, f''(x)=0.3 which is positive, We have minimum value.

So, the minimum value for  f(x) = 0.15(x + 1)^2 - 3 is -3.

7 0
3 years ago
The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi
slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}

Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

Simplifying the equation as

y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}

So the correct option is 4

8 0
3 years ago
Read 2 more answers
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