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lana [24]
4 years ago
6

The image produced by a convex mirror is always closer to the mirror than it would be in a plane mirror for the same object dist

ance. O True O False
Physics
1 answer:
rosijanka [135]4 years ago
6 0

Answer:

True

Explanation:

The image produced a convex mirror is always virtual irrespective of location. The size of the image is always smaller than the object. In a plane mirror the distance of the object and the distance of the image is same. But in a convex the image distance is always less than the object distance.

So, this statement is true.

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An electric motor can drive grinding wheel at two different speeds. When set to high the angular speed is 2000 rpm. The wheel tu
shutvik [7]

a) The initial angular speed is 209.3 m/s

b) The angular acceleration is -1.74 rad/s^2

c) The angular speed after 40 s is 139.7 rad/s

d) The wheel makes 1501 revolutions

Explanation:

a)

The initial angular speed of the wheel is

\omega_i = 2000 rpm

which means 2000 revolutions per minute.

We have to convert it into rad/s. Keeping in mind that:

1 rev = 2\pi rad

1 min = 60 s

We find:

\omega_i = 2000 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=209.3 rad/s

b)

To find the angular acceleration, we have to convert the final angular speed also from rev/min to rad/s.

Using the same procedure used in part a),

\omega_f = 1000 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=104.7 rad/s

Now we can find the angular acceleration, given by

\alpha = \frac{\omega_f - \omega_i}{t}

where

\omega_i = 209.3 rad/s is the initial angular speed

\omega_f = 104.7 rad/s is the final angular speed

t = 60 s is the time interval

Substituting,

\alpha = \frac{104.7-209.3}{60}=-1.74  rad/s^2

c)

To find the angular speed 40 seconds after the initial moment, we use the equivalent of the suvat equations for circular motion:

\omega' = \omega_i + \alpha t

where we have

\omega_i = 209.3 rad/s

\alpha = -1.74 rad/s^2

And substituting t = 40 s, we find

\omega' = 209.3 + (-1.74)(40)=139.7 rad/s

d)

The angular displacement of the wheel in a certain time interval t is given by

\theta=\omega_i t + \frac{1}{2}\alpha t^2

where

\omega_i = 209.3 rad/s

\alpha = -1.74 rad/s^2

And substituting t = 60 s, we find:

\theta=(209.3)(60) + \frac{1}{2}(-1.74)(60)^2=9426 rad

So, the wheel turns 9426 radians in the 60 seconds of slowing down. Converting this value into revolutions,

\theta = \frac{9426 rad}{2\pi rad/rev}=1501 rev

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

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The diagrams below represent different ways heat can be transferred on Earth. The arrows in the diagrams show the direction of h
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Answer:

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Potential energy is the ability to:
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