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muminat
2 years ago
5

WHY ARE ALL GIRLS THE SAME, don't even say their not cause if you say that then I guess you don't have a life!!!!!​

Physics
1 answer:
Zinaida [17]2 years ago
6 0
Because they are. it’s just how life works
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If you make multiple measurements of your height, you are likely to find that the results vary by nearly half an inch in either
Lisa [10]

Answer:

Height h= 1.7 m

Explanation:

Supposing we have to find height in meter.

1 feet = 0.3048 m

1 inch = 0.0254 m

Given that:

5 feet

= 5×0.3048

= 1.524 m

and 7 inch = 7×0.0254= 0.1778 m

Therefore total height of a man in meter

5 feet 7 inch = 1.5424+0.1778 =1.7 m

Height h= 1.7 m

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3 years ago
What evidence did astronomers use to prove jets travel in opposite directions?
mr Goodwill [35]

The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.

<h3>Who are the astronomers?</h3>

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Therefore, The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.

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7 0
2 years ago
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Pay it forward! Answer a questio1) For a positive point charge, the lines radiate ………. . While, for a negative point charge, the
nikitadnepr [17]

Explanation:

1) For a positive point charge, the lines radiate outwards

for a negative point charge, the lines converge inwards

2) F = 2.3 X 10^-26 N

k = 9 X 10^9 N.m²/C

q1 = q2 = e = 1.6 X 10^-19 C

r = ?

F = kq1q2/r²

r² = kq1q2/F

r = √[kq1q2/F ]

r = √0.0100

r = 0.10m

The two protons are 0.10 m apart

3) The unit if electric field intensity is Newton-per-coulomb N/C

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3 years ago
Question 3 of 10
Ahat [919]

Answer:

The unit of power is pascal.

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2 years ago
ball dropped from top of 50m high cliff stone thrown straight up from bottom with speed of 24. they collide. how far above base
Tresset [83]

Answer:

28.73 m from the base of the cliff collide happen

Explanation:

Equation for ball dropped from 50 cliff is reaches distance x in t seconds isi given by

x=ut+\frac{1}{2} at^2\\\\x= 0 \times t+\frac{1}{2} gt^2 =\frac{1}{2} gt^2......(1)

stone is thrown up from the bottom with speed u=24 m/s . it reaches distance y when stone collide with ball.(g is negative here)

y=24t-\frac{1}{2} gt^2.............(2)

we know that total distance traveled by ball and stone is 50 m

x+y=50 m

adding equation 1 and 2, we get time t

x+y=\frac{1}{2} gt^2+24t-\frac{1}{2}gt^2\\50=24t\\t=2.083 s

substitute this time in equation 2, we can get the required distance where they collide

y=24t-\frac{1}{2} gt^2\\y=24\times 2.083-\frac{1}{2}\times  9.8\times 2.083^2\\y=28.73 m

28.73 m from the base of the cliff collide happen

7 0
3 years ago
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