Answer:
thank u for the happiest year of my life life
The final velocity of the composite object is 6/5 m/sec.
<h3>
what is velocity?</h3>
- Velocity is the direction at which an item is moving and serves as a measure of the rate at which its location is changing as seen from a certain point of view and as measured by a specific unit of time (for example, 60 km/h northbound).
- In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a basic idea.
- A physical vector quantity called velocity must have both a magnitude and a direction in order to be defined.
- Speed is the scalar absolute value (magnitude) of velocity; it is a coherent derived unit whose quantity is measured in metres per second (m/s or m/s1) in the SI (metric system).
To learn more about the topic, refer to the following link:
brainly.com/question/80295?source=archive
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Answer:
9.8 × 10⁴Pa
Explanation:
Given:
Velocity V₁ = 12m/s
Pressure P₁ = 3 × 10⁴ Pa
From continuity equation we have
ρA₁V₁ = ρA₂V₂
A₁V₁ = A₂V₂
making V₂ the subject of the equation;

the pipe is widened to twice its original radius,
r₂ = 2r₁
then the cross-sectional area A₂ = 4A₁
⇒ 

This implies that the water speed will drop by a factor of
because of the increase the pipe cross-sectional area.
The Bernoulli Equation;
Energy per unit volume before = Energy per unit volume after
p₁ +
ρV₁² + ρgh₁ = p₂ +
ρV₂² + ρgh₂
Total pressure is constant and
= P =
ρV₂²ρV²
p₁ +
ρV₁² = p₂ +
ρV₂²
Making p₂ the subject of the equation above;
p₂ = p₁ +
ρV₁² -
ρV₂²
But
so,
p₂ = p₁ +
ρV₁² -
ρ
p₂ = 3.0 x 10⁴ + (
× 1000 × 12²) - (
× 1000 × 12²/4² )
P₂ = 3.0 x 10⁴ + 7.2 × 10⁴ - 4.05 x 10³
P₂ = 9.79 × 10⁴Pa
P₂ = 9.8 × 10⁴Pa
Answer:
Q₂ = 5833.33 J
Explanation:
First we need to find the energy supplied to the heat engine. The formula for the efficiency of the heat engine is given as:
η = W/Q₁
where,
η = efficiency of engine = 30% = 0.3
W = Work done by engine = 2500 J
Q₁ = Heat supplied to the engine = ?
Therefore,
0.3 = 2500 J/Q₁
Q₁ = 2500 J/0.3
Q₁ = 8333.33 J
Now, we find the heat discharged to lower temperature reservoir by using the formula of work:
W = Q₁ - Q₂
Q₂ = Q₁ - W
where,
Q₂ = Heat discharged to the lower temperature reservoir = ?
Therefore,
Q₂ = 8333.33 J - 2500 J
<u>Q₂ = 5833.33 J</u>
Time = distance divided by speed
4,900 divide 1.5 = 3266.67