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Alex777 [14]
2 years ago
10

A 60-W light bulb emits spherical electromagnetic waves uniformly in all directions. If 50% of the power input to such a light b

ulb is emitted as electromagnetic radiation, what is the radiation intensity at a distance of 2.00 m from the light bulb?
A) 15 W/m2
B) 4.8 W/m2
C) 2.4 W/m2
D) 0.60 W/m2
E) 1.2 W/m2
Physics
1 answer:
makkiz [27]2 years ago
4 0

Answer:

a

Explanation:

A 60-W light bulb emits spherical electromagnetic waves uniformly in all directions. If 50% of the power input to such a light bulb is emitted as electromagnetic radiation, what is the radiation intensity at a distance of 2.00 m from the light bulb    

so i did 60(50%)=30÷2=15

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Answer:

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Explanation:

Given;

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voltage of the wire, V = 120 V

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The resistivity of the wire, ρ = 1.68 x 10⁻⁸ Ω⋅m

Area of the wire;

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A = (π x 0.00289²) / 4

A = 6.561 x 10⁻⁶ m²

(a) At 26 m of this wire, the resistance of the is

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Resistance of the wire at 26 m length of wire and  1.366 x 10⁻⁵ m² area;

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R = (1.68 x 10⁻⁸  x 26) / 1.366 x 10⁻⁵

R = 0.032 Ω

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Answer:

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