You can do pencil and paper or use a calculator if necessary
Your answer is <em>3.5</em>
Answer: x = $7, y = $6
Step-by-step explanation:
Let x be the cost of an adult ticket
Let y be the cost of a children's ticket
Translate these sentences to algebra:
At the circus, three adult tickets and five child tickets cost $51: 3x + 5y = 51
Five adult tickets and two child tickets cost $47: 5x + 2y = 47
Now we have two equations. Let's use substitution to solve.
3x + 5y = 51
3x = 51 - 5y
.: x = 17 - 5y/3
Now substitute this value of x into the second equation to find the numerical value of y:
5(17 - 5y/3) + 2y = 47
85 - 25y/3 + 2y = 47
-19y/3 = -38
-19y = -114
.: y = 6
Now find x:
x = 17 - 5y/3
x = 17 - 10
.: x = 7
So an adult ticket costs $7, and a child ticket costs $6 :)
Answer:
b = -125/9
Step-by-step explanation:
1 + log5 ( -9b) = 4
Subtract 1 from each side
1 -1+ log5 ( -9b) = 4-1
log5 ( -9b) = 3
Raise each side to the base 5
5^ log5 ( -9b) = 5^3
This will cancel the log5
-9b = 125
Divide each side by 9
-9b/-9 = 125/-9
b = -125/9
