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3 years ago

If a sample of 2 moles of nitric oxide gas was reacted with excess oxygen, how many moles of nitrogen dioxide would be produced?

Chemistry

1 answer:

Oksana_A [137]3 years ago

6 0

Answer:

If a sample of 2 moles of nitric oxide gas was reacted with excess oxygen, 2 moles of nitrogen dioxide would be produced.

Explanation:

The balanced reaction is:

2 NO + O₂ → 2 NO₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

NO: 2 moles
O₂: 1 mole
NO₂: 2 moles

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop. By reaction stoichiometry, if a sample of 2 moles of nitric oxide gas was reacted with excess oxygen, 2 moles of nitrogen dioxide would be produced.

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The equations given in the problem introduction can be added together to give the following reaction: overall: N2O4→2NO2 However

Murljashka [212]

Answer:

Reverse the $2 NO_2 \longrightarrow 2 NO + O_2$ reaction

Explanation:

Reactions:

$2 NO_2 \longrightarrow 2 NO + O_2$

$N_2O_4 \longrightarrow 2 NO + O_2$

Overall:

$N_2O_4 \longrightarrow 2 NO_2$

As can be seen, in the overall reaction we have $N_2O_4$ in the reactants like in the second reaction and $NO_2$ in the products. The $NO_2$ is in the first reaction but as a reactant so we need to reverse that reaction:

$2 NO + O_2 \longrightarrow 2 NO_2$

$N_2O_4 \longrightarrow 2 NO + O_2$

Combining:

$N_2O_4 + 2 NO + O_2\longrightarrow 2 NO + O_2 + 2 NO_2$

$N_2O_4 \longrightarrow 2 NO_2$

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Alexeev081 [22]

Answer:

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18. For the recoton 2H2 + O2 + 2H20. how many moles of water can be produced from 23.2 mol of

grigory [225]

Answer:

23.2 mols

Explanation:

(23.2 mol H2)(2 mol H2O) /(2 mol H2) = 23.2 mol H2O

you have to do stoichiometry - so start of with what you are given, which is 23.2 mols of hydrogen, then to cancel out mols of hydrogen, divide by what is in the equation: so 23.2 mols H2 / 2 mols H2. Next, to get mols of H2O multiply that number by the mols of water in the equation.

this answer makes sense because as you can see in the equation, there are 2 H2:2 H2O, so the amounts should be the same.

hope this helps! make sure to practice because it is ESSENTIAL that you understand this, especially if you plan on taking ap chem. good luck! :)

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3 years ago