All categories

3 years ago

With which group would group 18 most likely bond

Chemistry

1 answer:

Mice21 [21]3 years ago

8 0

Answer:

The noble gases (Group 18) are located in the right of the periodic table and were previously referred to as the "inert gases" due to the fact that their filled valence shells (octets) make them extremely nonreactivE

Explanation:

You might be interested in

Solve and show work. Li2S + 2 HNO3 --> 2 LiNO3 + H2S (a) Calculate the mass of lithium sulfide that will react with 250 mL of

Elenna [48]

Li2S + 2 HNO3 --> 2 LiNO3 + H2S

Li2 S + H2 N2 O2 --> Li2 N2 O5 + H2 S

Li S + H2 N2 O5 -> Li N2 O5 + H2 S

Li2 S2 + H4 N4 O10 --> Li2 N4 O10 + H4 S2

Li^2 S^2 + H^4 N^4 O^10 --> Li^2 N^4 O^10 + H^4 S^2

7 0

2 years ago

If an electron fell to a lower orbit or energy level, energy would be

arsen [322]

It would emit energy in most of the cases in form of light

5 0

3 years ago

Read 2 more answers

Hòa tan hoàn toàn 1,93 gam hỗn hợp 2 kim loại Fe và Al vào dd HCl dư, sau phản ứng thu được m gam muối và 1,456 lít khí H2 ở đkt

Lostsunrise [7]

Answer:

Sorry pal! Didn't understand your language.

Explanation:

8 0

3 years ago

State property of the liquids that caused them to separate into layers

nydimaria [60]

Explanation:

Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension.

Source: https://en.m.wikipedia.org/wiki/Decantation

6 0

3 years ago

A person’s blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma

Elanso [62]

Answer:

0.17%

Explanation:

With the equation:

2Cr2O7 2- + C2H5OH + H2O --> 4Cr3+ + 2CO2 + 11H2O

We can assume that every mole of ethanol needs 2 moles of Dichromate to react.

So if in 1L we have 0.05961 moles of dichromate we can discover how many moles we have in 35.46mL

1000 mL - 0.05962 moles

35.46 mL - x

x = $\frac{0.05962 * 35.46}{1000}$

x = 2,11* 10^-3 moles

As we said earlier, 1 mole of ethanol needs 2 mole of dichromate, so in the solution we have 1,055*10^-3 moles of ethanol. We can discover the mass of ethanol present in the solution.

1 mole - 46g

1.055*10^-3 - y

y = 46 * 1.055*10^-3

y = 0.048 g

To discover the percent of alchol we can use a simple relation

28 g - 100%

0.048 - z

z = $\frac{0.048 * 100}{28}$

z = 0.17%

6 0

3 years ago