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Marat540 [252]
3 years ago
9

The equations given in the problem introduction can be added together to give the following reaction: overall: N2O4→2NO2 However

, one of them must be reversed. Which one?
Chemistry
1 answer:
Murljashka [212]3 years ago
4 0

Answer:

Reverse the 2 NO_2 \longrightarrow 2 NO + O_2  reaction

Explanation:

Reactions:

2 NO_2 \longrightarrow 2 NO + O_2

N_2O_4 \longrightarrow 2 NO + O_2

Overall:

N_2O_4 \longrightarrow 2 NO_2

As can be seen, in the overall reaction we have N_2O_4 in the reactants like in the second reaction and NO_2 in the products. The NO_2 is in the first reaction but as a reactant so we need to reverse that reaction:

2 NO + O_2 \longrightarrow 2 NO_2

N_2O_4 \longrightarrow 2 NO + O_2

Combining:

N_2O_4 + 2 NO + O_2\longrightarrow 2 NO + O_2 + 2 NO_2

N_2O_4 \longrightarrow 2 NO_2

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When an ionic compound such as sodium chloride (NaCl) is placed in water, the component atoms of the NaCl crystal dissociate int
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Answer:

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Explanation:

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b) <u>For covalent compounds</u>:

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The difference is a factor which is the number of particles resulting from the dissociation or ionization of one mole of the ionic compound.

So, calling M the molarity, you can write:

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This table show the calculations for the four solutions from the list of choices:

Compound    kind         Particles in solution  Molarity   # of particles

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A) NaCl          ionic            ions Na⁺ and Cl⁻        1.0            1.0 × 1 × 2 = 2

B) NaCl          ionic            ions Na⁺ anc Cl⁻        0.5           0.5 × 1 × 2 = 1

C) Glucose    covalent     molecules                   0.5          0.5 × 1 × 1 = 0.5

D) Glucose    covalent     molecules                   1.0           1.0 × 1  × 1 = 1

Therefore, the rank in increasing number of particles is for the list of solutions given is: C < B = D < A, which means that the solution expected to contain the greatest number of solute particles is the solution A) 1 L of 1.0 M NaCl.

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What class of elements do iron and nickel belong?
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IM THINKING THEY BELONG IN THIS CLASS OF ELEMENTS VILL B.
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5 0
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if the balance indicated that the evaporating dish has a mass of 44.8 g and you want to have exactly 5.0 g of copper. what shoul
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49.8 g should be the balance read.

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Adding the mass of the evaporation dish 44.8 g with the mass of the copper 5 g you obtain 49.8 g.

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