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worty [1.4K]
3 years ago
9

How to balance a equation ​

Chemistry
1 answer:
Alona [7]3 years ago
7 0

Answer:

Count the atoms of each element in the reactants and the products then use coefficients. You place them in front of the compounds if needed.

Hope this helps!

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For each set of dilutions (bleach and mouthwash), the first tube contained a 1:11 dilution (0.5 mL of agent was added to 5.0 mL
lidiya [134]

Answer:

Tube 2: 8.26 * 10^-3; Tube 4: 6.83 * 10^-5

Explanation:

In the serial dilutions for MIC test, the volume of nutrient broth in each tube should be equal: 5.0 mL. And the volume of agent in each dilution should also be similar: 0.5 mL.

The serial dilutions was as following:

  • Tube 1: 0.5/5.5
  • Tube 2: 0.5 mL of tube 1 was diluted with 5.0 mL broth. Then, the dilution of tube 2 is (1:11) * (1:11) = (0.5/5.5) * (0.5/5.5) = 1:121 = 8.26 * 10^-3
  • Tube 3: We perform the similar calculation. Thus, the result is 1:1331 = 7.51 * 10^-4
  • Tube 4: It is 1:14641 = 6.83 * 10^-5.

5 0
3 years ago
Which question is the student most likely trying to answer?
USPshnik [31]

Answer:

B in my opinion

Explanation:

7 0
3 years ago
Read 2 more answers
How many bonding domains around the central atom and nonbonding domains around the central atom are their in PF4Cl?
Greeley [361]

Answer:

NH2- has two pairs of bonding and two pairs of non-bonding electrons participated in the formation of a molecule. The central nitrogen atom has two pairs of non-bonding electrons cause repulsion on both bonding pairs which pushes the bonds closer to each other. So, NH2- has a bent (angular) molecular geometry.

Explanation:

7 0
3 years ago
0 ml of a 1.20 m solution is diluted to a total volume of 228 ml. a 114-ml portion of that solution is diluted by adding 111 ml
ozzi
54.0 ml of a 1.2 m solution was diluted to a total volume of 228 ml
USing dilution equation
M1V1 = M2V2
Where M1V1 is before dilution while M2V2 is after dilution.
Therefore;
M1= 1.20 M, V2= 54 ml,  
M2=              V2 = 228 ml

1.20 M × 54 ml = M2 × 228 ml
  M2 = (1.2 ×54)/ 228 ml
       = 0.2842 M

0.2842 × 114 ml = M2 × (114 +111)
      M2 = (0.2842 ×114)/ 225
            = 0.143995
            = 0.144 M

3 0
3 years ago
What can be found in the Asteroid Belt?
Akimi4 [234]

Answer:

astrioids can be found at the astrioid belt

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3 years ago
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