First of all we can draw a parallel line to divide the figure into a triangle and a rectangle as shown in the figure. To find the area of our rectangle, remember that the area of a rectangle is length times width, so
![A_{r} =lw](https://tex.z-dn.net/?f=A_%7Br%7D%20%3Dlw)
. Since we know for our figure that the length and width of our rectangle are 13cm and 6cm respectively, lets replace those values in our formula to get its area:
![A _{r} =(13cm)(6cm)](https://tex.z-dn.net/?f=A%20_%7Br%7D%20%3D%2813cm%29%286cm%29)
![A=78cm^{2}](https://tex.z-dn.net/?f=A%3D78cm%5E%7B2%7D%20)
Similarly, the area of a triangle is one half times base times height, so
![At=( \frac{1}{2})bh](https://tex.z-dn.net/?f=At%3D%28%20%5Cfrac%7B1%7D%7B2%7D%29bh%20)
. Since we know that our base is 8cm and our height 6cm, lets replace those values in our equation to find the area of our triangle:
![A_{t} =( \frac{1}{2})(8cm)(6cm)](https://tex.z-dn.net/?f=A_%7Bt%7D%20%3D%28%20%5Cfrac%7B1%7D%7B2%7D%29%288cm%29%286cm%29%20)
![A_{t} =24cm^{2}](https://tex.z-dn.net/?f=A_%7Bt%7D%20%3D24cm%5E%7B2%7D%20)
Now the only thing left is add our areas:
![A_{total} =78cm^{2}+24cm^{2} =102cm^{2}](https://tex.z-dn.net/?f=A_%7Btotal%7D%20%3D78cm%5E%7B2%7D%2B24cm%5E%7B2%7D%20%20%3D102cm%5E%7B2%7D%20)
We can conclude that the correct answer is <span>
A. 102</span>
What are your answer choices
X=-3
7+4x=-5
-7 -7
4x=-12
/4. 4/
X=-3
1)V=Ixwxh
=5 cm x 3 cm x 2 cm
=30 cm³
2)V=bxh
=(10m x 6m) x 4m
= 60 m² x4 m
3)V=Ixwxh
=3 cm x 3 cm x 3 cm =27 cm³
=240 m³
Step-by-step explanation:
J = 2b
M = J + 7
M = 21
J = 21 - 7
J = 14
B = 7
<em>Equation:</em>
If M is J+7, so then J = 21-7. J is 2*b, so 2*b = 21-7. Then you subtract and divide.