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Harrizon [31]
3 years ago
7

Which fraction is equivalent to the whole number 8? A.1/8 B.2/10 C.12/8 D.16/2

Mathematics
1 answer:
Tom [10]3 years ago
8 0

Answer:

D: 16/2

Step-by-step explanation:

you take 16 and divide it by 2 making your answer 8

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I don’t understand please help me and give the answer
barxatty [35]
Which question do u need help with
4 0
3 years ago
What is 3 to the powers of 5
My name is Ann [436]

Answer:

3 to the power of 5 = 35 = 243

Step-by-step explanation:

4 0
3 years ago
Please help me! ASAP!!!!!
Greeley [361]

Answer:

x=36

Step-by-step explanation:

17+3 =20

now we have :

x+4

___         = 20

  2

20*2= 40

x+4=40

x=36

hopes this helps

4 0
2 years ago
Find the​ P-value for the indicated hypothesis test with the given standardized test​ statistic, z. Decide whether to reject H0
Leviafan [203]

Answer: We do not reject the null hypothesis.

Step-by-step explanation:

  • When the p-value is greater than the significance level , then we do not reject the null hypothesis or if p-value is smaller than the significance level , then we reject the null hypothesis.

Given : Test statistic : z = -2.28

Significance level : \alpha=0.02

By using the standard normal distribution table ,

The p-value corresponds to the given test statistic ( two tailed ):-

2P(Z>|z|)=2P(Z>2.28)=0.0226

Since the p-value is greater than the significance level of 0.02.

Then , we do not reject the null hypothesis.

8 0
3 years ago
Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.064

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

6 0
2 years ago
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