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Dovator [93]
2 years ago
14

Sample Data - Grignard Reagents Reaction Characterization Type of reaction: choose the general type of reaction from the options

Write the balanced equation for the formation of the Grignard reagent from bromobenzene. Include all reagents and products but not solvents. Write the balanced equation for the formation of benzoic acid from the Grignard reagent. Include all reagents and products but not solvents.
Chemistry
1 answer:
attashe74 [19]2 years ago
8 0

Grignard reagent consists of any of numerous organic derivatives of magnesium (Mg), commonly represented by the general formula RMgX (in which R is a hydrocarbon radical: CH3, C2H5, C6H5, etc.; and X is a halogen atom, usually chlorine, bromine, or iodine).

What are Grignard Reagents?

In synthetic processes, Grignard reagents are used to create new carbon-carbon bonds. A extremely polar carbon-magnesium bond, in which the carbon atom has a partial negative charge and the metal a partial positive charge, characterizes a Grignard reagent.

The balanced equation for the formation of the Grignard reagent from bromobenzene is in the image.

To learn more about Grignard reagent visit:

brainly.com/question/20985645

#SPJ4

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4 0
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⦁ Find the concentration of H+, OH-, PH and POH of 0.03 M of magnesium hydroxide which ionizes to the extent of only 1 /3 in aqu
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Answer:

pH=12.3\\\\pOH=1.7\\

[H^+]=5x10^{-13}M

[OH^-]=0.02M

Explanation:

Hello there!

In this case, according to the given ionization of magnesium hydroxide, it is possible for us to set up the following reaction:

Mg(OH)_2(s)\rightleftharpoons Mg^{2+}(aq)+2OH^-(aq)

Thus, since the ionization occurs at an extent of 1/3, we can set  up the following relationship:

\frac{1}{3} =\frac{x}{[Mg(OH)_2]}

Thus, x for this problem is:

x=\frac{[Mg(OH)_2]}{3}=\frac{0.03M}{3}\\\\x=  0.01M

Now, according to an ICE table, we have that:

[OH^-]=2x=2*0.01M=0.02M

Therefore, we can calculate the H^+, pH and pOH now:

[H^+]=\frac{1x10^{-14}}{0.02}=5x10^{-13}M

pH=-log(5x10^{-13})=12.3\\\\pOH=14-pH=14-12.3=1.7

Best regards!

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