Sample Data - Grignard Reagents Reaction Characterization Type of reaction: choose the general type of reaction from the options
1 answer:
Grignard reagent consists of any of numerous organic derivatives of magnesium (Mg), commonly represented by the general formula RMgX (in which R is a hydrocarbon radical: CH3, C2H5, C6H5, etc.; and X is a halogen atom, usually chlorine, bromine, or iodine).
What are Grignard Reagents?
In synthetic processes, Grignard reagents are used to create new carbon-carbon bonds. A extremely polar carbon-magnesium bond, in which the carbon atom has a partial negative charge and the metal a partial positive charge, characterizes a Grignard reagent.
The balanced equation for the formation of the Grignard reagent from bromobenzene is in the image.
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Answer:
[O₃]= 8.84x10⁻⁷M
Explanation:
<u>The photodissociation of ozone by UV light is given by:</u>
O₃ + hν → O₂ + O (1)
<u>The first-order reaction of the equation (1) is:</u>
(2)
<em>where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration </em>
<u>We can get the following expression of the </u><u>first-order integrated law</u><u> of the reaction (1), by resolving the equation (2):</u>
(3)
<em>where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration</em>
We can calculate the initial ozone concentration using equation (3):
So, the ozone concentration after 10 days is 8.84x10⁻⁷M.
I hope it helps you!
<u>Answer:</u> The mass of PVB required to produce 1000 grams of tape is 213.4 grams
<u>Explanation:</u>
To calculate the mass of aluminium oxide, we use the equation:
.......(1)
- <u>For
</u>
We are given:
50% (v/v) of
This means that 50 mL of aluminium oxide is present in 100 mL of tape
Calculating the mass of aluminium oxide by using equation 1:
Density of aluminium oxide =
Volume of aluminium oxide = (Conversion factor:
)
Putting values in equation 1, we get:
Mass of aluminium oxide = 199 g
- <u>For PVB:</u>
We are given:
50% (v/v) of PVB
This means that 50 mL of PVB is present in 100 mL of tape
Calculating the mass of PVB by using equation 1:
Density of PVB =
Volume of PVB =
Putting values in equation 1, we get:
Mass of PVB = 54 g
Mass of tape = Mass of aluminium oxide + mass of PVB
Mass of tape = [199 + 54] g = 253 g
To calculate the mass of PVB required to produce 1000 g of tape, we use unitary method:
When 253 grams of tape is made, the mass of PVB required is 54 g
So, when 1000 grams of tape is made, the mass of PVB required will be =
Hence, the mass of PVB required to produce 1000 grams of tape is 213.4 grams