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statuscvo [17]
2 years ago
5

Find the domain and range of the exponential function h(x)= -343^x

Mathematics
1 answer:
givi [52]2 years ago
7 0
I will named this exponential function as y= - 343^x .
This function is symmetrical with function y = 343^x in relation to X axis. 
In general their formula is y=a^x or in your case y= - a^x

First I'll describe y=a^x => this function has domein Dx=R ( Whole field of real number), range is in interval ( 0,  +infinity), when x increases and y increases, when x decreases and y decreases. This function is always positive in whole domain and always is growing function. And X axis is its asymptote (y=0).

In your case function y= - 343^x has folowing features:
domein Dx=R
range is in interval (-infinity, 0)
when x increases => y decreases =>
example: y= -2^2=-4, y= -2^3=-8 etc....
when x decreases => y increases ->
example: y= -2^(-2)= - 1/(2^2)= - 1/4, y=-2^(-3)= - 1/(2^3)= - 1/8 etc....
this function is always negative
this function is always declining
x axis is its asymptote from the top ( y=0)
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Y=-4x-2 and intersects at the points (4,-1)
rosijanka [135]

Answer:

It doesn't intersect at that point

{ \bf{y =  - 4x - 2}} \\ y =  - (4 \times 4) - 2 \\ y =  - 18

4 0
3 years ago
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6 high school seniors choose from among 20 quotes for their yearbook. What is the probability that at least 2 of them choose the
shusha [124]

Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • There are 6 students, hence n = 6.
  • There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.

The probability of one quote being chosen at least two times is given by:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351

P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328

0.0328 = 3.28% probability that at least 2 of them choose the same quote.

More can be learned about the binomial distribution at brainly.com/question/24863377

6 0
2 years ago
1.Find the dot product of the two given vectors, u=(1,6) and v=(-5,-2) 2. Find the dot product of v=-7i+4j and w=-6i+5j
Svet_ta [14]
The dot product of the two vectors will be given as follows:
v*w=(-7i+4j)*(-6i+5j)
=(-7*(-6))i+(4*5)j
=-42i+20j

Hence the answer is:
v*w=(-42i+20j)
8 0
3 years ago
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shepuryov [24]
1.Combine multiplied terms into a single fraction

2. Multiply by 1

3. Subtract 6 from both sides of the equation

4.Simplify

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8.Simplify

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What is the slope of the line that is perpendicular to the given line x-2y=10?
Anuta_ua [19.1K]

Answer: slope = 1/2

Step-by-step explanation:

X-2y=10

-2y=-x-10 subtract x from both sides

2y=x+10 divide by -1

y=<u>1</u> x + 5 Divide by 2

  2

slope = 1/2

6 0
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