Question

Calculate the heat change in calories for vaporization of 30.0g of water at 100degrees C

Answer 1

Answer:

1.62 × 10⁴ cal

Explanation:

Step 1: Given and required data

• Mass of water (m): 30.0 g

• Latent heat of vaporization of water (ΔH°vap): 540 cal/g

Step 2: Calculate the heat change (Q) for vaporization of 30.0g of water at 100 °C

The vaporization is a phase change in which water passes from the liquid state to the gaseous state. We can calculate the heat required using the following expression.

Q = ΔH°vap × m

Q = 540 cal/g × 30.0 g

Q = 1.62 × 10⁴ cal