Answer:
2.4 moles of oxygen are needed to react with 87 g of aluminium.
Explanation:
Chemical equation:
4Al(s) + 3O₂(l) → 2AlO₃(s)
Given data:
Mass of aluminium = 87 g
Moles of oxygen needed = ?
Solution:
Moles of aluminium:
Number of moles of aluminium= Mass/ molar mass
Number of moles of aluminium= 87 g/ 27 g/mol
Number of moles of aluminium= 3.2 mol
Now we will compare the moles of aluminium with oxygen.
Al : O₂
4 : 3
3.2 : 3/4×3.2 = 2.4 mol
2.4 moles of oxygen are needed to react with 87 g of aluminium.
56.0774 g/mol just took the test
I think it's calorie
Hope this helps
Answer:
1) 0.423 m
2) 3.107 mi
3) 68.18 kg
4) 0.0083 mem
5) 0.528 gal
6) 4300 mL
7) 32.4 mem
8) 523.013 km
9) 70.866 in
10) 2.3 yek
Note: I can’t type the about equal to sign or the sign that shows a repeating decimal, so check the image for that and my work.
Explanation:
Answer:
In atomic physics, the Bohr model or Rutherford–Bohr model, presented by Niels Bohr and Ernest Rutherford in 1913, is a system consisting of a small, dense nucleus surrounded by orbiting electrons—similar to the structure of the Solar System, but with attraction provided by electrostatic forces in place of gravity.
Explanation:
