Write the chemical equation for the reaction of propylamine, c3h7nh2 with water.

Chemistry

2 answers:

maw [93]2 years ago

8 0

The reaction of propylamine with water gives a hydrogen shift from water molecule to amine group of propylamine.

$\boxed{{{\text{C}}_{\text{3}}}{{\text{H}}_{\text{7}}}{\text{N}}{{\text{H}}_{\text{2}}}+{{\text{H}}_{\text{2}}}{\text{O}}\to{{\text{C}}_{\text{3}}}{{\text{H}}_{\text{7}}}{\text{NH}}_3^+ + {\text{O}}{{\text{H}}^ -}}$

Further explanation:

Acids and bases can be defined in many ways based on different theories, which are as follows:

According to Arrhenius theory, acid is defined as the one which produces hydrogen ions in a solution, while the base is defined as the one which produces hydroxide ions in a solution.

According to Bronsted–Lowry theory, the acid in the reaction donates a proton while a base is one that accepts a proton.

According to Lewis theory, the acid in the reaction accepts a pair of electrons while a base donates a pair of electrons.

The propylamine contains amine $\left({-{\text{N}}{{\text{H}}_2}}\right)$ group. Amine $\left({-{\text{N}}{{\text{H}}_2}}\right)$ group is a basic group that can accept a proton from proton donor species because of the lone pair of nitrogen.

The water $\left({{{\text{H}}_2}{\text{O}}}\right)$ molecule has acidic hydrogen and thus water can behave as a proton donor molecule.

The water will release the proton to form ${\text{O}}{{\text{H}}^-}$ and propylamine will accept the proton to form ${{\text{C}}_{\text{3}}}{{\text{H}}_{\text{7}}}{\text{NH}}_3^+$ .

The complete reaction of propylamine with water gives a hydrogen shift from water molecule to amine group of propylamine as follows:

${{\text{C}}_{\text{3}}}{{\text{H}}_{\text{7}}}{\text{N}}{{\text{H}}_{\text{2}}}+{{\text{H}}_{\text{2}}}{\text{O}}\to{{\text{C}}_{\text{3}}}{{\text{H}}_{\text{7}}}{\text{NH}}_3^++{\text{O}}{{\text{H}}^-}$