<u>Given:</u>
Volume of HCl = 150 ml
Molarity of HCl = 0.10 M
<u>To determine:</u>
The # moles of HCl
<u>Explanation:</u>
The molarity of a solution is the number of moles of a solute dissolved in a given volume
In this case:
Molarity of HCl = moles of HCl/volume of the solution
moles of HCl = Molarity * volume = 0.10 moles.L-1 * 0.150 L = 0.015 moles
Ans: A)
Moles of HCl is 0.015
<h3>
Answer:</h3>
1.07 M
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Molarity = moles of solute / liters of solution
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 2.14 moles (CH₃)₂SO
[Given] 2.00 L
[Solve] Molarity
<u>Step 2: Solve</u>
- Substitute in variables [Molarity]: x M = 2.14 moles (CH₃)₂SO / 2.00 L solution
- [Molarity] Divide: x = 1.07 M
Is the combination of all forces acting on an object
<span>the behavior of the above pair of substances</span> is soluble
Answer:
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