All categories

2 years ago

7. Suppose a compact car uses 1 gallon of fuel for every 27 miles

Mathematics

2 answers:

weeeeeb [17]2 years ago

5 0

Answer:

Id need to see the graph!

Step-by-step explanation:

Yakvenalex [24]2 years ago

5 0

Compact car equation
Y=27x
Graph that and see what you got for car

You might be interested in

Ratio of 34 inches to 1 foot

ololo11 [35]

Answer:

34:12

Step-by-step explanation:

5 0

3 years ago

Solve the system of equations below algebraically <br> 2x+3y=6 and -5x+2y=4

Charra [1.4K]

Steps
I’m using elimination so I’m trying to get rid of y
To do that I multiply the first equation by 2 and the second by -3. Then solve
4x + 6x = 12
15x + -6x = -12
—————————
19x + 0 = 0
Divid by 19 to get x to one side. 0/19 is 0 so
X= 0
Plug that into an equation so 0 + 3y = 6
Divid by 3 and y = 2
Answer x = 0 y = 2

7 0

3 years ago

Simplify square root of five times the quantity six minus four square root of three.

NemiM [27]

6√5 - 4√3-

i took the test but sorry if its wrong

5 0

2 years ago

Of the following options, what could be a possible first step in solving the equation 3x − 1 = 2x + 4? Combining like terms, 3x

faust18 [17]

<span>Subtracting 2x from both sides of the equation would be a reasonable first step in solving this equation as it properly combines like terms to the left side of the equation. It quickly shows that the next step would be adding 1 to both sides of the equation, which would have us arrive at the answer of x = 5.</span>

8 0

3 years ago

Read 2 more answers

Create a matrix for this system of linear equations, The determinant of the coefficient matrix is

marin [14]

Answer: The determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

Step-by-step explanation: The given system of linear equations is :

$2x+y+3z=13~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\x+2y=11~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\3x+z=10~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

We are given to find the determinant of the coefficient matrix and to find the values of x, y and z.

The determinant of the co-efficient matrix is given by

$D=\begin{vmatrix}2 & 1 & 3\\ 1 & 2 & 0\\ 3 & 0 & 1\end{vmatrix}=2(2-0)+1(0-1)+3(0-6)=4-1-18=-15.$

Now, from equations (ii) and (iii), we have

$x+2y=11~~~~~\Rightarrow y=\dfrac{11-x}{2}~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)\\\\\\3x+z=10~~~~~~\Rightarrow z=10-3x~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Substituting the value of y and z from equations (iv) and (v) in equation (i), we get

$2x+y+3z=13\\\\\Rightarrow 2x+\dfrac{11-x}{2}+3(10-3x)=13\\\\\Rightarrow 4x+11-x+60-18x=26\\\\\Rightarrow -15x+71=26\\\\\Rightarrow -15x=26-71\\\\\Rightarrow -15x=-45\\\\\Rightarrow x=3.$

From equations (iv) and (v), we get

$y=\dfrac{11-3}{2}=4,\\\\z=10-3\times3=1.$

Thus, the determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

3 0

3 years ago