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1 year ago

Can someone help please 3x-y=13 A. (6,5) B.(3,-4) C. (6,5) and (3,-4) D. neither

Mathematics

2 answers:

Katen [24]1 year ago

8 0

Answer: c

Step-by-step explanation:

lol

gavmur [86]1 year ago

6 0

Answer:

C. (6, 5) and (3, -4)

Step-by-step explanation:

Given the equation 3x - y = 13, we need to figure out which points satisfy it. In order for an ordered pair to satisfy an equation, when we plug the x-coordinate in for x and the y-coordinate in for y, the equation should hold true.

Let's try with (6, 5):

3x - y = 13

3 * 6 - 5 =? 13

18 - 5 =? 13

13 = 13

Since this is true, we know that (6, 5) is indeed a solution.

Now let's try with (3, -4):

3x - y = 13

3 * (3) - (-4) =? 13

9 + 4 =?13

13 = 13

Again, since this is true, then (3, -4) must be a solution.

Thus, the answer is C.

<em>~ an aesthetics lover</em>

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Find the x- and y-intercepts of the graph of the linear equation.<br> 2x+3y=12

Arisa [49]

Answer:

y intercept: (0, 4); x intercept: (6, 0)

Step-by-step explanation:

to find the x and y intercepts of the line we can plug numbers in

we can turn x into 0 to find the y intercept

2(0) + 3y = 12

0 + 3y = 12

y = 4

this means that your y intercept is (0, 4)

then we can turn y into 0 to find the x intercept

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this means that your x intercept is (6, 0)

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1 year ago

Sean earns $8.50 per hour and made a total of $80.75 today. How many hours did he work?

Vesnalui [34]

Answer: 9.5 hours

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Step-by-step explanation:

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2 years ago

Which equation is the inverse of y = 9x2 - 4?

m_a_m_a [10]

Answer:

The inverse will be:

$y' = \frac{\sqrt{x+4}}{3}$

Step-by-step explanation:

In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :

$f(x) = 9x^{2} - 4$

$y = 9x^{2} - 4$

$x = 9y' ^{2} - 4$

Now solve for y'.

First add 4 in both sides of the equation and change to the left y'.

$x + 4= 9y'^{2} - 4+4$

$9y'^{2}$ = x + 4

Second divide by 9

$9y'^{2}$ /9 = (x + 4)/9

$y'^{2}$ = (x + 4)/9

Now you will have to clear y, with the square root.

$[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}$ [/tex] =

Simplifying terms

$y' = \frac{\sqrt{x+4}}{3}$

$f^{-1}(x) = \frac{\sqrt{x+4}}{3}$

You can check the answer by doing the evaluation of the following equation:

(f o $f^{-1}$ ) (x)

substitute the equation for y' or inverse function $f^{-1}$

f( $\frac{\sqrt{x+4} }{3}$ )

Now substitue the value into f(x)

You will have

$= 9(\frac{\sqrt{x+4} }{3}} )^{2} - 4\\\\Solving\\\\9(\frac{{x+4} }{9}} ) - 4$

5 0

2 years ago

A bowling alley has a fixed base cost and charges a variable per game rate. It costs $20.50 for five games and 28.50 for nine ga

lbvjy [14]

As ordered pairs ( g , C ) where g is the number of games and C is the cost

( 5, 20.50) and ( 9, 28.50)

the slope M = ( 28.50 - 20.50 ) / (9-5)

= 8/4

= 2

So the slope M=$2 per game

Using (5, 20.50)
The intercept B = y - m* g
= 20.50 - 2 * 5
= 20.50 - 10
= 10.50

So the fixed base cost, or FLAT RATE is $10.50.
That is if they played ZER0 games, they still have
to pay $10.50 just to get in.

The linear function is C (g) = 2*g + 10.50

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2 years ago

Complete a piecewise function that describes the graph.

trapecia [35]

Answer:

$y=\left \{ \begin{array}{l}-x^2-4x-1,\ x$

Step-by-step explanation:

Left part of the graph is the graph of the parabola passing through the points (-2,3), (-3,2) and (-4,-1). If the equation of the parabola is $y=ax^2+bx+c,$ then

$3=a\cdot (-2)^2+b\cdot (-2)+c\Rightarrow 3=4a-2b+c\\ \\2=a\cdot (-3)^2+b\cdot (-3)+c\Rightarrow 2=9a-3b+c\\ \\-1=a\cdot (-4)^2+b\cdot (-4)+c\Rightarrow -1=16a-4b+c$

Subtract first two equations and last two equations:

$-1=5a-b\\ \\-3=7a-b$

Suybtract these two equations:

$-2=2a\Rightarrow a=-1$

So $-1=5\cdot (-1)-b\Rightarrow b=-5+1=-4$

Substitute into the first equation:

$3=4\cdot (-1)-2\cdot (-4)+c\Rightarrow c=3+4-8=-1$

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The right part of the graph is translated 1 unit to the right and 1 unit down graph of the function $y=\dfrac{1}{2}|x|$ , so it has the equation $y=\dfrac{1}{2}|x-1|-1$

Hence, the piece-wise function is

$y=\left \{ \begin{array}{l}-x^2-4x-1,\ x$

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2 years ago