Answer:
Local atmospheric pressure in kPa = 97.932 kPa
Local atmospheric pressure in mm Hg = 734.78 mm Hg
Explanation:
Given:
= absolute pressure = 46 kPa = 46000 kPa
= density of air = ![0.828\ kg/m^3](https://tex.z-dn.net/?f=0.828%5C%20kg%2Fm%5E3)
= density of mercury = ![13600\ kg/m^3](https://tex.z-dn.net/?f=13600%5C%20kg%2Fm%5E3)
= altitude of the plane = 6400 m
Assume:
= pressure decrease due to air at height h
= local atmospheric pressure
As we go up the altitude, the pressure decreases. So, the reading of the pressure will be equal to the decrease in pressure due to height subtracted from the local atmospheric pressure.
![\therefore Absolute\ pressure = Atmospheric\ pressure - Pressure\ decrease\\\Rightarrow P_a=P_{atm}-P_h\\\Rightarrow P_{atm}=P_a+P_h\\\Rightarrow P_{atm}=46000+\rho_a g h\\\Rightarrow P_{atm}=46000+0.828\times 9.8\times 6400\\\Rightarrow P_{atm}=97932.16\ Pa\\\Rightarrow P_{atm}=97.932\ kPa](https://tex.z-dn.net/?f=%5Ctherefore%20Absolute%5C%20pressure%20%3D%20Atmospheric%5C%20pressure%20-%20Pressure%5C%20decrease%5C%5C%5CRightarrow%20P_a%3DP_%7Batm%7D-P_h%5C%5C%5CRightarrow%20P_%7Batm%7D%3DP_a%2BP_h%5C%5C%5CRightarrow%20P_%7Batm%7D%3D46000%2B%5Crho_a%20g%20h%5C%5C%5CRightarrow%20P_%7Batm%7D%3D46000%2B0.828%5Ctimes%209.8%5Ctimes%206400%5C%5C%5CRightarrow%20P_%7Batm%7D%3D97932.16%5C%20Pa%5C%5C%5CRightarrow%20P_%7Batm%7D%3D97.932%5C%20kPa)
Now, conversion of the local atmospheric pressure is quite simple. let us assume that height of H mm of Hg is required to exert a pressure equivalent to the local atmospheric pressure.
![\therefore P_{atm}= \rho_h g H\\\Rightarrow H = \dfrac{P_{atm}}{\rho_h g}\\\Rightarrow H = \dfrac{97932.16\ Pa}{13600\ kg/m^3 \times 9.8\ m/s^2}\\\Rightarrow H = 0.73478\ m\\\Rightarrow H =734.78\ mm](https://tex.z-dn.net/?f=%5Ctherefore%20P_%7Batm%7D%3D%20%5Crho_h%20g%20H%5C%5C%5CRightarrow%20H%20%3D%20%5Cdfrac%7BP_%7Batm%7D%7D%7B%5Crho_h%20g%7D%5C%5C%5CRightarrow%20H%20%3D%20%5Cdfrac%7B97932.16%5C%20Pa%7D%7B13600%5C%20kg%2Fm%5E3%20%5Ctimes%209.8%5C%20m%2Fs%5E2%7D%5C%5C%5CRightarrow%20H%20%3D%200.73478%5C%20m%5C%5C%5CRightarrow%20H%20%3D734.78%5C%20mm)
Hence, 734.78 mm Hg is the local atmospheric pressure in mm Hg.
Answer:
C
Explanation:
I think it could be C because, gasoline which is used by cars is a big factor in more emission being placed in the air. With electrical powered cars like Tesla, emission can decrease.
Sorry if i'm wrong
But, hope this helps :)
Answer:
T = 144°C
Explanation:
From the law conservation of energy,
Heat loss = Heat gain
mc(T-50) = 2mc(50-3)
T-50 = 2(47)
T-50 = 94
T = 94+50
T = 144°C
Plz check it out
Answer:
d = 2,011,661.81 m
The distance of the spaceship from the earth is d = 2,011,661.81 m
Explanation:
Let t1 represent the time taken for sound to travel between the astronaut and t2 the the time taken for electromagnetic waves to travel from the spaceship to earth.
Given;
t1 = t2
t1 = distance apart/speed of sound in air
t1 = 2.30/343 = 0.0067055 seconds
t2 = t1 = 0.0067055 seconds
Speed of electromagnetic waves v2 = 3.0 × 10^8 m/s
Distance of the spaceship from the earth is d;
d = speed v2 × time t2
d = 3.0 × 10^8 m/s × 0.0067055 s
d = 2,011,661.81 m
The distance of the spaceship from the earth is d = 2,011,661.81 m
Stand on a planet with a radius that is shrinking