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Ipatiy [6.2K]
4 years ago
15

What is a four chord song??

Physics
1 answer:
Agata [3.3K]4 years ago
4 0

E, B, C# minor and A for the most songs

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What does the symbol 'Mg' represent?​
RSB [31]

Answer:

the \: symbol \: mg \: represent \: magnesium \\ thank \: you

3 0
3 years ago
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Maggie is a member of her school’s environmental club and is interested in recycling. She asks the question, “How does exposure
adell [148]

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C

Explanation:

Environmental factors provides ambiguity a particular one could be studied to see how it affects recyclable plastics.

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4 years ago
Which of the following statements are true? Check all that apply. Check all that apply. The gravitational force between two obje
uysha [10]

Explanation:

The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically, it is given by :

F\propto \dfrac{m_1m_2}{r^2}

F=G \dfrac{m_1m_2}{r^2}...............(1)

Where m₁ and m₂ are masses

r is the distance between them

It is clear from equation (1) that :

1. The gravitational force between two objects is inversely proportional to the square of the distance between the two objects.

2. The gravitational force between two objects is proportional to the product of the masses of the two objects.

Hence, this is the required solution.

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3 years ago
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A car traveling initially at 7.35 m/s acceler-
Flura [38]

Answer:

v_f=9,07~m/s

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes uniformly in time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

v_f=v_o+at

The car initially travels at vo=7.35 m/s and accelerates at a rate of a=0.824~m/s^2 during t=2.09 s.

The final velocity is:

v_f=7.35+0.824*2.09

\mathbf{v_f=9,07~m/s}

4 0
3 years ago
A 21.0 kg shopping cart is moving with a velocity of 4.0 m / s. It strikes a 7.0 kg box that is initially at rest. They stick to
jonny [76]

Explanation:

Given that,

Mass of the shopping cart, m_s=21\ kg

Initial speed of the shopping cart, u_s=4\ m/s

Mass of the box, m_b=7\ kg

Initial speed of the box, u_b=0 (at rest)

They stick together and continue moving at a new velocity. It is a case of inelastic collision.

(a) The momentum of the shopping cart before the collision is given by :

p_s=m_s\times u_s\\\\p_s=21\times 4\\\\p_s=84\ kg-m/s

(b) The momentum of the box before the collision is given by :

p_b=m_b\times u_b\\\\p_b=7\times 0\\\\p_b=0

(c) The velocity of the combined shopping cart/box wreckage after the collision is given by using the conservation of momentum as :

m_su_s+m_bu_b=(m_s+m_b)V\\\\V=\dfrac{m_su_s+m_bu_b}{(m_s+m_b)}\\\\V=\dfrac{21\times 4+0}{(21+7)}\\\\V=3\ m/s

Hence, this is the required solution.

8 0
3 years ago
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