Slope intercept form
y = mx + b
P1 (5,11)
M = -1/2.
Y - y1 = m(X - X1)
Y - 11 = -1/2(X - 5)
Y - 11 = -1/2X + 5/2
Y - 11 + 11 = -1/2X + 5/2 + 11
Y = -1/2X + 5/2 + 11
Y = -1/2X + 5/2 + 22/2
Y = -1/2X + 27/2
Y = -1/2X + 27/2. I believe this is the equation of the line in slope intercept form. I basically used slope point formula y-y1 = m(X-x1), to find the new equation of the line, inputting the value of the slope along with the point the line would go through.
Who knows, it is weird and impossible
Answer:
woooooooooooooooooooooo
Step-by-step explanation:
wooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo