Find the range of projectile launched at the angle of 45 with an intial velocity of 25 m/s

Physics

1 answer:

Mekhanik [1.2K]3 years ago

5 0

Answer:

Explanation:

Given that :

Initial Velocity (u) = 25 m/s

Range can be obtained using the relation :

Range = (u² * sin2θ) / g

g = 10m/s ; θ = 45

Range = [10² * sin2(45)] / 10

Range = [100 * 1] ÷ 10

Range = 10

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