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3 years ago

As an object is raised to a higher position,Which type of energy increases?

2 answers:

8 0

As the object is raised higher, its gravitational potential energy increases which is denoted in a formulae as gpe = mgh where m is mass, g is gravitational accelaration and h is height.
Therefore height increases proportionally to gpe if mass and acceleration are kept constant!

If you need further help over this topic, I will be more than happy to help you out, just message me!

Hope this helps!

Marizza181 [45]3 years ago

7 0

By raising a position of an object, Its potential energy increases.

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Which quantity does not change when there is an increase in temperature?

AysviL [449]

Answer:

But Mass of solids does not depend upon the temperature because it is matter contained in the solids.

Explanation:

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3 years ago

In the space around a permanent magnet, where is the magnetic field the strongest?

BlackZzzverrR [31]

near the north and south poles of the magnet

Explanation:

Magnetic fields around a permanent magnet is strongest near the north and south poles of the magnet.

Magnetic fields are the region of space around a magnet where magnetic effects are felt.

This is as a result of a force field that surrounds the magnet.
Magnetic fields are strongest within the magnet.
Also, externally, they are strongest at the poles of a magnet.
Around the poles, magnetic lines of force leaves and enters a magnet.

learn more;

Electromagnet brainly.com/question/2191993

#learnwithBrainly

6 0

3 years ago

A "seconds pendulum" is one that moves through its equilibrium position once each second. (The period of the pendulum is precise

Alex73 [517]

<h2>Ratio of free fall acceleration of Tokyo to Cambridge = 0.998</h2>

Explanation:

We know the equation

$T=2\pi \sqrt{\frac{l}{g}}$

where l is length of pendulum, g is acceleration due to gravity and T is period.

Rearranging

$g= \frac{4\pi^2l}{T^2}$

Length of pendulum in Tokyo = 0.9923 m

Length of pendulum in Cambridge = 0.9941 m

Period of pendulum in Tokyo = Period of pendulum in Cambridge = 2s

We have

$\frac{ g_{\texttt{Tokyo}}}{ g_{\texttt{Cambridge}}}= \frac{\frac{4\pi^2 l_{\texttt{Tokyo}}}{ T_{\texttt{Tokyo}}^2}}{\frac{4\pi^2 l_{\texttt{Cambridge}}}{ T_{\texttt{Cambridge}}^2}}\\\\\frac{ g_{\texttt{Tokyo}}}{ g_{\texttt{Cambridge}}}=\frac{\frac{0.9923}{2^2}}{\frac{0.9941}{2^2}}=0.998$

Ratio of free fall acceleration of Tokyo to Cambridge = 0.998

6 0

3 years ago

Which unit would be most appropriate for measuring the mass of a black bean?

madam [21]

Answer:

milligrams

explanation:

kilograms are too big

<em>Hope this helps :)</em>

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4 years ago

A carnot cycle engine operates between a low temperature reservoir at 20°c and a high temperature reservoir at 800°c. if the eng

Bogdan [553]

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8 0

3 years ago