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3 years ago

You are pedaling forward on your bike. which of the following would decrease your acceleration?

Physics

1 answer:

Minchanka [31]3 years ago

7 0

B. An increase in your mass

Because acceleration is inversely proportional to the mass of the object.

$a∝ \frac{1}{m}$

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A dentist’s drill starts from rest. After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min. Find the

mylen [45]

Answer:

Angular acceleration, is $708.07\ rad/s^2$

Explanation:

Given that,

Initial speed of the drill, $\omega_i=0$

After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed, $\omega_f=28940\ rev/min=3030.58\ rad/s$

We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.

$\alpha =\dfrac{\omega_f}{t}\\\\\alpha =\dfrac{3030.58\ rad/s}{4.28\ s}\\\\\alpha =708.07\ rad/s^2$

So, the drill's angular acceleration is $708.07\ rad/s^2$ .

4 0

3 years ago

On a sunny day, does a bird or an aeroplane flying high in the sky cast its

Ilia_Sergeevich [38]

Answer:

Hope it helps

Explanation:

The higher the bird flies, the bigger the shadow it casts, however, for the shadow to be visible enough the plane or bird would have to be close to the line directly from the sun.

3 0

3 years ago

Read 2 more answers

Scientists use this part of the electromagnetic spectrum to diagnose broken bones.

lesantik [10]

They use x-rays to diagnose broken bones

7 0

3 years ago

Read 2 more answers

When you push a 2.00 kg book resting on a tabletop it takes 4.60 N to start the book sliding. What is the coefficient of static

natali 33 [55]

The coefficient of static friction is 0.234.

Answer:

Explanation:

Frictional force is equal to the product of coefficient of friction and normal force acting on any object.

So here the mass of the object is given as 2 kg, so the normal force will be acting under the influence of acceleration due to gravity.

Normal force = mass * acceleration due to gravity

Normal force = 2 * 9.8 = 19.6 N.

And the frictional force is given as 4.6 N, then

$Coefficient of static friction = Frictional force/Normal force$

Coefficient of static friction = 4.6 N / 19.6 N = 0.234

So the coefficient of static friction is 0.234.

3 0

2 years ago

A small block of mass m on a horizontal frictionless surface is attached to a horizontal spring that has force constant k. The b

Rashid [163]

Answer:

$v_{max} = |d|\cdot \sqrt{\frac{k}{m} }$

Explanation:

The maximum speed of the block occurs when spring has no deformation, that is, there is no elastic potential energy, which can be remarked from appropriate application of the Principle of Energy Conservation:

$\frac{1}{2}\cdot k \cdot d^{2} = \frac{1}{2}\cdot m \cdot v^{2}$

$k \cdot d^{2} = m\cdot v^{2}$

$v_{max} = |d|\cdot \sqrt{\frac{k}{m} }$

5 0

3 years ago