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alexandr402 [8]
3 years ago
15

You are pedaling forward on your bike. which of the following would decrease your acceleration?

Physics
1 answer:
Minchanka [31]3 years ago
7 0

B. An increase in your mass

Because acceleration is inversely proportional to the mass of the object.

a∝ \frac{1}{m}

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The atomic mass of gold is 0.197 kg/mole. how many moles are in 0.566 kg of gold.
iogann1982 [59]

Explanation:

0.566kg *(1mol/0.197 kg)= 2.87 mol gold

note how the units cancel out, if the units do not cancel out (kg/kg=1) then u did something wrong

7 0
3 years ago
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A sinusoidal wave travels along a string. if the time for a particular point to move from maximum displacement to zero displacem
Lisa [10]
The time it takes for a point to reach 0 displacement from maximum displacement is \frac{\pi}{2} of a cycle. Thus, one period (2\pi) will take T=0.17*4=0.68s.

The frequency is simply f=\frac{1}{T}=\frac{1}{0.68}=1.47Hz.

The speed is given by: v=f\lambda=1.47*1.4 = 2.06m/s
7 0
3 years ago
what is the ratio of ey,final, the maximum value of the y-component of the electric field immediately following the last polariz
OleMash [197]

That ratio is 2 .

<h3>What is ratio?</h3>

A ratio is the  comparison of the  two numbers bydivision.

Taking the first two outputs, or the  -1/8 and -1/4, we can divide not the second one by the first one to find the

ratio:

-1/4-1/8

When dividing fractions, we multiply by the reciprocal:

-1/4x-8/1

To multiply fractions, multiply straight across:

(-1x-8)/(4x1) 8/4=2

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brainly.com/question/25927869

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8 0
1 year ago
Transformers will not work on ______ electrical systems.
Andru [333]

Transformers only work with AC.

If you put DC into a transformer, all that comes out is smoke.

(a)

5 0
3 years ago
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A 2.0-Coulomb bead is given 20 Joules of electric potential energy by lifting it from the "ground" to point A. If a second bead
Katen [24]

Answer:

40 J

Explanation:

c_1 = 4 C

c_2 = 2 C

U_1 = 20 J

The potential energy is directly proportional to the charge of the particle

U\propto c

\dfrac{U_2}{U_1}=\dfrac{c_2}{c_1}\\\Rightarrow U_2=\dfrac{U_1c_2}{c_1}\\\Rightarrow U_2=\dfrac{20\times 4}{2}\\\Rightarrow U_2=40\ J

The potential energy expected is 40 J

4 0
3 years ago
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