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kicyunya [14]
2 years ago
14

The graph in the accompanying figure (Figure 1) shows the magnitude of the force exerted by a given spring as a function of the

distance x the spring is stretched.
Figure1 of 1
A graph of force F as a function of distance x. The force is measured from 0 to 350 newtons on the vertical axis. The distance is measured from 0 to 8 centimeters on the horizontal axis. A graph curve starts from the origin and rises linearly to approximately 7 centimeters and 350 newtons.
Part A
How much work is needed to stretch this spring a distance of 2.0 cm, starting with it unstretched.
Express your answer in joules to two significant figures.


W =
nothing
J
Request Answer
Part B
How much work is needed to stretch this spring from 5.0 cm to 7.0 cm?
Express your answer in joules to two significant figures.


W =
nothing
J
Request Answer
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Physics
1 answer:
serious [3.7K]2 years ago
4 0

The elastic potential energy stored in the stretched spring is 1 J.

<h3>What is Hooke's law?</h3>

Hooke's law states that; provided the elastic limit is not exceeded, the extension of the spring is directly proportional to the force on the spring.

Given that;

Force on the spring = 350 Newton

Distance stretched = 7 centimeters or 0.07 m

Hence;

F = ke

k = F/e = 350 Newton/0.07 m = 5000 N/m

Work done in stretching a spring = 1/2ke^2

= 0.5 × 5000 × (2 × 10^-2)^2 =1 J

Learn more about elastic potential energy: brainly.com/question/156316

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Answer:

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b) 4000N

Explanation:

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S = (v+u)*t/2

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t = 0.05s

b) If we happened to calculate the avarage force we have to consider about acceleration

V= 0

U = 10

t = 0.05 s

a =?

V = U + at

0 = 10 -a * 0.05

a = 200 m/s2

F = m *a

= 20 * 200

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Two pool balls, each moving at 2 m/s, roll toward each other and collide. Suppose after bouncing apart, each moves at 2 m/s. Thi
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Answer:D

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Answer:

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Explanation:

Applying,

P = V²/(R₁+R₂).................. Equation 1

Where P = Power, V = Voltage, R₁ and R₂ = values of the two resistor.

From the question,

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