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lara [203]
3 years ago
5

PLEASE HELLPPP ITS FIR A FINAL 3.Speed (v) abs wavelength ( λ ) and the frequency (f) of sound are related asRequired to answer.

Single choice.Immersive Reader
(1 Point)
λ= v X f
v= λ X f
f= λ X v
v= λ / f
Physics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

B. v = λ X f

<em><u>Hope this helps! </u></em>

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The_____ of a substance is the temperature at which a solid begins to liquefy
kotykmax [81]

Answer:

Melting point

Explanation:

when a solid turns to a liquid, it is melting

6 0
3 years ago
Read 2 more answers
a net force of 1,800 N is applied to a boat causing it to accelerate at 1.5 m/s^2. what is the mass of the boat?
Xelga [282]

Answer:

<h3>The answer is 1200 kg</h3>

Explanation:

The mass of an object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{1800}{1.5}  \\

We have the final answer as

<h3>1200 kg</h3>

Hope this helps you

7 0
4 years ago
a 5.0 kg block is at rest on a horizontal floor. if you push horizontally on the 5.0 kg block with a force of 15.0 n, it just st
zheka24 [161]

For the 5.0Kg block with the force of 15 Newton, the coefficient of static friction (μ) comes out to be 0.306. Applying the formula F = μmg.

Static friction acts on stationary body/body at rest. Let μ be the coefficient of static friction between the block and the horizontal floor.

Using the formula: F = μmg

Where,

F = Force , m= mass of the block and g = gravity.

and values of: m= 5.0Kg, F= 15.0N, g= 9.8m/s²

We can get: μ = F/(mg)

μ = 15/49

μ =0.306

Therefore, coefficient of static friction (μ) = 0.306.

To learn more about static friction visit the link- brainly.com/question/13680415

#SPJ4

4 0
2 years ago
A dog starts at position x = 2.50 m, and undergoes a displacement of 8.25 m. What is its final position?
Jet001 [13]

Answer: 10.75 m

Explanation:

Displacement is how far the dog is from its original position, so use addition

initial + displacement = final

2.50 + 8.25 = 10.75

5 0
3 years ago
Un tren va a una velocidad de 18m/s frena y se detiene en 15s calcula su aceleracion y la distancia recorrida al frenar
Rudiy27

Answer:

Acceleration is -1.2 m/s² and distance covered is 135 m.

Explanation:

A train going at a speed of 18m / s brakes and stops in 15s calculates its acceleration and the distance traveled when braking

Given that,

The initial speed of the train, u = 18 m/s

Final speed, v = 0

Time, t = 15 s

We need to find acceleration and distance traveled when braking. Let a is acceleration and distance traveled.

Acceleration,

a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18}{15}\\\\a=-1.2\ m/s^2

Using third equation of motion,

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-18^2}{2\times (-1.2)}\\\\d=135\ m

Hence, acceleration is -1.2 m/s² and distance covered is 135 m.

3 0
3 years ago
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