The answer will be: 1,000,000 if you round to the nearest hundred thousands. Hope it helps! :D
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
Answer:
principal (p)=$35000
time(t)=8years
rate ( r)=7%
Step-by-step explanation:
- compounded amount(c.a)=p((1+r/100)^t )=$35000((1+7/100)^8)=$60136.5
- compound interest gain=$60136.5-$35000=$25136.5
- Karl gain interest in 1 year=$35000((1+7/100)-1)=$2450
- gain % in 1 year=$2450/$25136.5×100%=9.74%
Answer:
I dont understand the context of the question but something eqqual to that would be -6/8
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
8x+4(4x+3)=4(6x+4)−4
8x+(4)(4x)+(4)(3)=(4)(6x)+(4)(4)+−4(Distribute)
8x+16x+12=24x+16+−4
(8x+16x)+(12)=(24x)+(16+−4)(Combine Like Terms)
24x+12=24x+12
24x+12=24x+12
Step 2: Subtract 24x from both sides.
24x+12−24x=24x+12−24x
12=12
Step 3: Subtract 12 from both sides.
12−12=12−12
0=0
Answer:
All real numbers are solutions.
