Please help if you want brianleist!! :) uhm don't mind update- NO LINkS child..
1 answer:
You might be interested in
The answer is
first you must multiply or use the FOIL method (First, Outer, Inner, Last)
First you multiply the first terms
this gives you 3x^2, then you multiple the outer terms
this gives you -21x, then you multiply the inner terms
that gives you 2x, finally you multiply the last terms
that gives you 14, now you combine like terms
now you put all the terms together and end up with your solution
first you must multiply or use the FOIL method (First, Outer, Inner, Last)
First you multiply the first terms
this gives you 3x^2, then you multiple the outer terms
this gives you -21x, then you multiply the inner terms
that gives you 2x, finally you multiply the last terms
that gives you 14, now you combine like terms
now you put all the terms together and end up with your solution
In terms of algebra, writing "am" is the same as writing "a*m" or "a times m"
To undo the multiplication, we use division. We will divide both sides by m to get 'a' all by itself on the left side
So...
am = n+p
a*m = n+p
(a*m)/m = (n+p)/m .... divide both sides by m
a = (n+p)/m ... notice how the 'm's cancel out when we divide on the left side
Final Answer: a = (n+p)/m
You must use parenthesis to indicate that all of "n+p" is over m or you can write it like this
To undo the multiplication, we use division. We will divide both sides by m to get 'a' all by itself on the left side
So...
am = n+p
a*m = n+p
(a*m)/m = (n+p)/m .... divide both sides by m
a = (n+p)/m ... notice how the 'm's cancel out when we divide on the left side
Final Answer: a = (n+p)/m
You must use parenthesis to indicate that all of "n+p" is over m or you can write it like this