Answer:
187 moles NH₃
Explanation:
To find the amount of ammonia formed, you need to multiply the given value by the mole-to-mole ratio consisting of both relevant molecules. The mole-to-mole ratio is made up of the molecules' coefficients in the balanced equation. The desired unit should be placed in the numerator of the ratio. The final answer should have 3 sig figs to reflect the lowest amount of sig figs among the given values.
1 N₂ + 3 H₂ ----> 2 NH₃
^ ^
93.5 moles N₂ 2 moles NH₃
---------------------- x ------------------------- = 187 moles NH₃
1 mole N₂
1. Physical
2. D
3. It’s either A or D but I think it’s A
4. C
5. A
6. D
7. A
8. B
9. I couldn’t see the question for it
10. A
11. D
12. D
13. B
Answer:
1.0190 x 10⁻⁵ mol
Explanation:
We know the titration required 10.19 mL of 0.001000 M KIO₃, from this information we can calculate the number of moles KIO₃ reacted and from there the number of moles of ascorbic acid since it is a monoprotic acid ( 1 equivalent of ascorbic acid to one equivalent KIO₃).
Molarity = mol/V
V KIO₃ = 10.19 mL = 10.19 mL x 1 L/1000 mL = 0.01019 L
⇒ mol KIO₃ = V x M = 0.01019 L x 0.0010 mol / L = 1.0190 x 10⁻⁵ mol KIO₃
# mol ascorbic acid = # mol KIO₃ = 1.0190 x 10⁻⁵ mol
Answer:

Explanation:
Hello there!
In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:

Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:

Then, we plug in the variables to obtain:

Regards!