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3 years ago

Which law states that the entropy of the universe is always increasing?

2 answers:

5 0

Second law of thermodynamics states entropy of the universe is always increasing. entropy always increases in a spontaneous process .

option B) second law of thermodynamics

for example if we keep a hot cup of coffee the heat is lost to surrounding and entropy( randomness increases) since it is a natural process entropy of universe increases.

svetoff [14.1K]3 years ago

4 0

Answer:

b. second law of thermodynamics

Explanation:

Entropy (S) is a measure of the extent of disorder or randomness of a system. Greater the disorder, higher (more positive) will be the entropy.

According to the second law of thermodynamics the energy of an isolated system always increases and evolves towards thermal equilibrium. Since the universe is essentially an isolated system, it implies that the entropy of the universe is always increasing.

The change in entropy (ΔS) is given in terms of the ratio of thermal energy of the system (q) and temperature (T). SI unit is J/K

$\Delta S=\frac{q}{T}$

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An ocean trench .

Klio2033 [76]

Answer:

C. Occurs where a plate is moving down.

Explanation:

Ocean trenches are steep depressions in the deepest parts of the ocean where old ocean crust from one tectonic plate is pushed beneath another plate, raising mountains, causing earthquakes, and forming volcanoes on the seafloor and on land.

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7 0

3 years ago

Read 2 more answers

Calculate the unit cell edge length for an 85 wt% fe-15 wt% v alloy. All of the vanadium is in solid solution, and, at room temp

Lady bird [3.3K]

Answer is 0.289nm.

Explanation: The wt % of Fe and wt % of V is given for a Fe-V alloy.

wt % of Fe in Fe-V alloy = 85%

wt % of V in Fe-V alloy = 15%

We need to calculate edge length of the unit cell having bcc structure.

Using density formula,

$\rho_{ave}=\frac{Z\times M_{ave}}{a^3\times N_A}$

For calculating edge length,

$a=(\frac{Z\times M_{ave}}{\rho_{ave}\times N_A})^{1/3}$

For calculating $M_{ave}$ , we use the formula

$M_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{V}}{M_V}}$

Similarly for calculating $(\rho)_{ave}$ , we use the formula

$\rho_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{\rho_{Fe}}+\frac{(wt\%)_{V}}{\rho_V}}$

From the periodic table, masses of the two elements can be written

$M_{Fe}= 55.85g/mol$

$M_{V}=50.941g/mol$

Specific density of both the elements are

$(\rho)_{Fe}=7.874g/cm^3\\(\rho)_{V}=6.10g/cm^3$

Putting $M_{ave}$ and $\rho_{ave}$ formula's in edge length formula, we get

$a=\left [\frac{Z\left (\frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{Fe}}{M_{Fe}}} \right )}{N_A\left (\frac{100}{\frac{(wt\%)_V}{\rho_V}+\frac{(wt\%)_V}{\rho_V}} \right )} \right ]^{1/3}$

$a=\left [\frac{2atoms/\text{unit cell}\left (\frac{100}{\frac{85\%}{55.85g/mol}+\frac{15\%}{50.941g/mol}} \right )}{(6.023\times10^{23}atoms/mol)\left (\frac{100}{\frac{85\%}{7.874g/cm^3}+\frac{15\%}{6.10g/cm^3}} \right )} \right ]^{1/3}$

By calculating, we get

$a=2.89\times10^{-8}cm=0.289nm$

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3 years ago

Which of the following is an important application of hydrogen bonding

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3 years ago

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Under what conditions does the molar volume of a gas decrease

nydimaria [60]

Answer:

Gases are compressible, meaning that when put under high pressure, the particles are forced closer to one another. This decreases the amount of empty space and reduces the volume of the gas. Gas volume is also affected by temperature. When a gas is heated, its molecules move faster and the gas expands.

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Find the number of Li atoms in 1.50 mole of Li

ale4655 [162]

The molar mass of Li->7g/mol
If 1mol of Li is 7g/mol
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3 years ago