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3 years ago

2.70 feet is the same as how many cm?

Chemistry

1 answer:

finlep [7]3 years ago

8 0

about 82.2 centimetres.

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The molar solubility of silver bromide, AgBr in pure water is 0.0007350 mol/L. What is the

gayaneshka [121]

Answer:

0.000000540

Explanation:

Step 1: Make an ICE chart for the solution of AgBr

"S" represents the molar solubility of AgBr

AgBr(s) ⇄ Ag⁺(aq) + Br⁻(aq)

I 0 0

C +S +S

E S S

Step 2: Write the expression for the solubility product constant (Ksp)

Ksp = [Ag⁺] [Br⁻] = S × S

Ksp = S² = (0.0007350)² = 0.000000540

7 0

3 years ago

Help help help ASFAP

gulaghasi [49]

Answer:

A directory of relatives' phone numbers

Hope this helps

Explanation:

5 0

3 years ago

In an endothermic reaction, a drop in temperature would be observed.<br><br> TRUE<br> or <br> FALSE

zvonat [6]

The answer is True! Hope this helps correct me if I’m wrong

8 0

4 years ago

Read 2 more answers

A chemist uses hot hydrogen gas to convert chromium(III) oxide to

Darya [45]

Answer: 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$

Explanation:

The reaction equation for given reaction is as follows.

$Cr_{2}O_{3} + 3H_{2} \rightarrow 2Cr + 3H_{2}O$

Here, 1 mole of $Cr_{2}O_{3}$ reacts with 3 moles of $H_{2}$ .

As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide $(Cr_{2}O_{3})$ is 152 g/mol.

Number of moles is the mass of substance divided by its molar mass. So, moles of $Cr_{2}O_{3}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{76 g}{152 g/mol}\\= 0.5 mol$

Now, moles of $H_{2}$ .given by 0.5 mol of $Cr_{2}O_{3}$ is calculated as follows.

$0.5 mol Cr_{2}O_{3} \times \frac{3 mol H_{2}}{1 mol Cr_{2}O_{3}}\\= 1.5 mol H_{2}$

As molar mass of $H_{2}$ is 2.016 g/mol. Therefore, mass of $H_{2}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\1.5 mol = \frac{mass}{2.016 g/mol}\\mass = 3.024 g$

Thus, we can conclude that 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$ .

7 0

3 years ago

4. Fill in the blanks. Complete each sentence using a term from the word bank. (4)

skelet666 [1.2K]

Answer:

A.compound genuinely bozo L XL so

4 0

3 years ago